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laiz [17]
3 years ago
14

Science questions!! Please help!!

Physics
1 answer:
kondor19780726 [428]3 years ago
7 0

Answer:

1. b

2. c

3. b

4. a

5. a

6. c

7. c

8. d

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Vectors and have scalar product -9.00 and their vector product has magnitude 7.00.
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<span>-(-(-)(-)(-10x))=-5 solve for x</span>
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3 years ago
Point charge A is located at point A and point charge B is at point B. Points A and B are separated by a distance r. To determin
fredd [130]

Answer:

B. The algebraic sum of the two electric potentials is determined at a distance r/2 from each of the charges, making sure to include the signs of the charges.

Explanation:

Total electric potential is the sum of all the electric potential. And because electric potential is a scalar quantity you have to account for the signs.

3 0
3 years ago
Please help me with this i dont know it​
Inessa05 [86]

Answer:

no it would not. that is an open circuit and it would need to be closed at the switch for current to flow.

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3 years ago
A cannon is rigidly attached to a carriage, which can move along horizontal rails but is connected to a post by a large spring,
Mademuasel [1]

Answer:

Explanation:

Given

mass of cannon and cart is m_1=6475.91 kg

Spring constant k=20000 N/m

mass of Projectile m_2=234 kg

Launch Velocity of cannon v_2=170 m/s

Launch angle \theta =31.3^{\circ}

As the External Force is zero therefore we can conserve momentum

Initially both Projectile and cannon is at rest

Conserving momentum in horizontal direction

m_1u_1+m_2u_2=m_1v_1+m_2v_2\cos 31.3

0+0=6475.91\times v_1+234\times 170\cdot \cos (31.3)

v_1=-\frac{234\times 170\cdot \cos (31.3)}{6475.91}

v_1=-5.24 m/s

i.e. cannon is moving in opposite direction of Projectile

6 0
4 years ago
Keeping the applied voltage constant at approximately 0.70 volts, measure the electric field strength at different points betwee
Vitek1552 [10]

Answer: I observed that the electric field strength is the same at all points between the plates. The value of the field is 70 volts per meter. This is exactly 100 times the applied voltage. The electric field lines point from the positive plate to the negative plate, as the downward arrow on the detector shows.

Explanation:

the sample answer, don't directly copy it!

3 0
2 years ago
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