Answer:
13 and 16
Step-by-step explanation:
let the 2 parts be x and y, then
x + y = 29 → (1) and
x² + y² = 425 → (2)
From (1) → x = 29 - y → (3)
substitute x = 29 - y into (2)
(29 - y)² + y² = 425 ( expand factor )
841 - 58y + y² + y² = 425 ( rearrange into standard form )
2y² - 58y + 416 = 0 ← in standard quadratic form
divide all terms by 2
y² - 29y + 208 = 0
Consider the factors of 208 which sum to - 29
These are - 13 and - 16, hence
(y - 13)(y - 16) = 0
equate each factor to zero and solve for y
y - 13 = 0 ⇒ y = 13
y - 16 = 0 ⇒ y = 16
substitute these values into (3)
x = 29 - 13 = 16 and x = 29 - 16 = 13
The 2 parts are 13 and 16
Hey mate !!
Here's your answer !!
2w^2 - 11w = -12
2w^2 -11w + 12 = 0
2w^2 - 8w - 3w + 12 = 0
2w ( w - 4) -3 ( w - 4) = 0
(2w - 3) ( w - 4) = 0
Hence
2w - 3 = 0
2w = 3
w = 3/2
w - 4 = 0
w = 4
Hence value of w are 4 and 3/2
Hope this helps!!
Cheers!!
Answer:
6370 is the answer Hope this helps.
<h3>
Answer:</h3>
761680
<h3>
Explanation:</h3>

<u>Identify the following's</u>:
First Term [a] = 60(1.2)ⁿ⁻² = 60(1.2)¹⁻² = 50
Common ratio [r] = 1.2
Total Terms [n] = 44
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Solving Steps:
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The team-lead gets $2000 if the team of 3 QA testers and l QA team lead is working on a project. The team finishes the job and is paid.
<h3>What is average?</h3>
It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.
Let's suppose the team lead salary is x and the team-lead receives, $600 more than the average salary of the entire team then,
The team lead salary:

4x = 3600+ x+ 2400
3x = 6000
x = $2000
Thus, the team lead gets $2000 if the team of 3 QA testers and l QA team lead is working on a project. The team finishes the job and is paid.
Learn more about the average here:
brainly.com/question/24057012
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