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Elis [28]
3 years ago
9

When a force is parallel to an axis ot has ......that axis​

Engineering
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0

Explanation:

In the poem, I refers to the poet. He says that he wants to go to Innisfree. He will build a small room with the help of clay. He will make the walls of the rooms with small sticks. He will grow the nine rows of the bean near his home. He will also have the honeybee from which he can collect fresh honey. He says that his room will be full of the buzzing sound of bees and he will live alone in peace and silence there.

In the second stanza, the poet says that he feels peace in the Innisfree island. He will feel peace enveloping him gradually. Further, he says that in the morning, when the clouds cannot be seen clearly, then it appears as the morning has worn a cover. This scene will make him feel more serene. He says that he enjoys the morning song of the cricket insect. At midnight, the twinkling in the sky gives him immense pleasure. In the afternoon, the purple glow of the sunlight makes him feel happy and in the evening, he enjoys the scene of the linnet birds flying in the sky with their full wings.

In the last stanza, the poet is determined to go to Innisfree. He says that he will now stand up and go to Innisfree because day or night, all the time in his mind he hears the sound of the lake water hitting the shore. Whenever he stands in the city, on the roadway or on the grey coloured pavement, he hears the sound deep inside his heart.

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Two very long concentric cylinders of diameters D1 = 0.42 m and D2 = 0.5 m are maintained at uniform temperatures of T1 = 950 K
MrRa [10]

Answer:

Q=33.34 KW/m

Explanation:

Given that

D₁=0.42 m

A₁= π D₁ L

For unit length

A₁= π D₁ = 0.42 π m²

D₂=0.5 m

A₂= 0.5 π m²

ε₁= 1 ,ε₂= 0.55

T₁=950 K  ,T₂ = 500 K

Q=\dfrac{\sigma (T_1^4-T_2^4)}{\dfrac{1-\varepsilon _1}{A_1\epsilon _1}+\dfrac{1-\varepsilon _2}{A_2\epsilon _2}+\dfrac{1}{A_1F_{12}}}

F₁₁+F₁₂= 1

F₁₁= 0

So, F₁₂= 1

Q=A_1\dfrac{\sigma (T_1^4-T_2^4)}{\dfrac{1-\varepsilon _1}{\epsilon _1}+A_1\dfrac{1-\varepsilon _2}{A_2\epsilon _2}+1}

Q=0.42\pi \dfrac{5.67\times 10^{-8}(950^4-500^4)}{\dfrac{1-1}{1}+0.42\pi\times \dfrac{1-0.55}{0.5\pi\times 0.55}+1}

Q=33.34 KW/m

3 0
4 years ago
What is a heat engine? State its efficiency (a sketch would be appropriate).
dimulka [17.4K]

Answer:

\eta =\dfrac{Q_1-Q_2}{Q_1}

Explanation:

Heat engine

 Heat engine is a device which produce work while consuming some amount of energy .This engine works in cycle.In other words we can say that Heat engine is a device which covert thermal or chemical energy in to mechanical energy and after that this mechanical energy can be use for producing mechanical work.

Heat engine takes heat from high temperature and rejects heat to lower temperature and producing work.

We know that efficiency given as

\eta =\dfrac{out\ put}{in\ put}

From diagram we can say that

Q_1=Q_2+W

So efficiency

\eta =\dfrac{w}{Q_1}

\eta =\dfrac{Q_1-Q_2}{Q_1}

3 0
3 years ago
A 2 m3 insulated rigid tank contains 3 kg of nitrogen at 90 kPa. Now work is done on the system until the pressure in the tank r
Nutka1998 [239]

Answer: \Delta S = 1.47kJ/K

Explanation: <u>Entropy</u> is the measure of a system's molecular disorder, i.e, the unuseful work a system does.

The nitrogen gas in the insulated tank can be described as an ideal gas, so it can be used the related formulas.

For the entropy, the ratio of initial and final temperatures is needed and as volume is constant, we use:

\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}

\frac{P_{2}}{P_{1}} =\frac{T_{2}}{T_{1}}

\frac{T_{2}}{T_{1}} =\frac{175}{90}

\frac{T_{2}}{T_{1}} =1.94

<u>Specific</u> <u>Heat</u> is the quantity of heat required to increase the temperature 1 degree of a unit mass of a substance. Specific heat of nitrogen at constant volume is c_{v}= 0.743kJ/kg.K

The change in entropy is calculated by

\Delta S= m[c_{v}ln(\frac{T_{2}}{T_{1}})-Rln(\frac{V_{2}}{V_{1}} )]

For the nitrogen insulated in a rigid tank:

\Delta S= m[c_{v}ln(\frac{T_{2}}{T_{1}})]

Substituing:

\Delta S= 3[0.743ln(1.94)]

\Delta S= 1.47

The entropy change of nitrogen in an insulated rigid tank is 1.47kJ/K

6 0
3 years ago
Consider weather conditions for which the prevailing wind blows past the penthouse tower on a tall building. The tower length in
ANTONII [103]

Answer:

Please find attached file for complete answer solution and explanation of same question.

Explanation:

3 0
3 years ago
A 150-lbm astronaut took his bathroom scale (a spring scale) and a beam scale (compares masses) to the moon where the local grav
kozerog [31]

Answer:

a)Wt =25.68 lbf

b)Wt = 150 lbf

F= 899.59 N

Explanation:

Given that

g = 5.48 ft/s^2.

m= 150 lbm

a)

Weight on the spring scale(Wt) = m g

We know that

1\ lbf=32.17 \ lmb.ft/s^2

Wt = 150 x 5.48/32 lbf

Wt =25.68 lbf

b)

On the beam scale

This is scale which does not affects by gravitational acceleration.So the wight on the beam scale will be 150 lbf.

Wt = 150 lbf

If the plane is moving upward with acceleration 6 g's then the for F

F = m a

We know that

1\ ft/s^2= 0.304\ m/s^2

5.48\ ft/s^2= 1.66\ m/s^2

a=6 g's

a=9.99\ m/s^2

So

F = 90 x 9.99 N

F= 899.59 N

3 0
3 years ago
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