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bixtya [17]
3 years ago
7

What is a heat engine? State its efficiency (a sketch would be appropriate).

Engineering
1 answer:
dimulka [17.4K]3 years ago
3 0

Answer:

\eta =\dfrac{Q_1-Q_2}{Q_1}

Explanation:

Heat engine

 Heat engine is a device which produce work while consuming some amount of energy .This engine works in cycle.In other words we can say that Heat engine is a device which covert thermal or chemical energy in to mechanical energy and after that this mechanical energy can be use for producing mechanical work.

Heat engine takes heat from high temperature and rejects heat to lower temperature and producing work.

We know that efficiency given as

\eta =\dfrac{out\ put}{in\ put}

From diagram we can say that

Q_1=Q_2+W

So efficiency

\eta =\dfrac{w}{Q_1}

\eta =\dfrac{Q_1-Q_2}{Q_1}

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Technician A says that a lack of lubrication on the back of the disc brake pads can cause brake noise. Technician B says that pa
sweet-ann [11.9K]

Answer:

Technician A and B both are correct.

Explanation:

According to Technician A, we can stop noise by applying lubricant (Break friction).

According to Technician A, we can stop noise by set-up right position for break pad.

7 0
3 years ago
Help please all of the numbers b4 the equal sign are wrong
Nostrana [21]

Answer:

  • 3/5" = 12'
  • 1 3/4" = 35'
  • 1 1/4" = 25'
  • 9/10" = 18'
  • 2 13/20" = 53'

Explanation:

One number is wrong; they all lack units.

The basic ratio is 1" = 20', so you can divide feet by 20 to find inches.

  • 3/5" = 12'
  • 1 3/4" = 35'
  • 1 1/4" = 25'
  • 9/10" = 18'
  • 2 13/20" = 53'

Perhaps you want decimal inches:

  • 0.60" = 12'
  • 1.75" = 35'
  • 1.25" = 25'
  • 0.90" = 18'
  • 2.65" = 53'
7 0
3 years ago
What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 5 × 10-4
White raven [17]

Answer:

The question is a problem that requires the principles of fracture mechanics.

and we will need this equation below to get the Max. Stress that exist at the tip of an internal crack.

Explanation:

Max Stress, σ = 2σ₀√(α/ρ)

where,

σ₀  = Tensile stress = 190MPa = 1.9x10⁸Pa

α  = Length of the cracked surface = (4.5x10⁻²mm)/2 = 2.25x10⁻⁵m

ρ  = Radius of curvature of the cracked surface = 5x10⁻⁴mm = 5x10⁻⁷m

Max Stress, σ = 2 x  1.9x10⁸ x (2.25x10⁻⁵/5x10⁻⁷)⁰°⁵

Max Stress, σ = 2 x  1.9x10⁸ x 6.708 Pa

Max Stress, σ = 2549MPa

Hence, the magnitude of the maximum stress that exists at the tip of an internal crack = 2549MPa

7 0
4 years ago
Why will screws never replace nails​
cupoosta [38]

Answer:

because people have different opinions on nails and screws

Explanation:

3 0
4 years ago
Please help meh!!! I appreciate it!
Rasek [7]

Answer:

★ The answers ARE B,A,D,D,A !

Explanation:

Hope you have a great day

7 0
3 years ago
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