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bixtya [17]
2 years ago
7

What is a heat engine? State its efficiency (a sketch would be appropriate).

Engineering
1 answer:
dimulka [17.4K]2 years ago
3 0

Answer:

\eta =\dfrac{Q_1-Q_2}{Q_1}

Explanation:

Heat engine

 Heat engine is a device which produce work while consuming some amount of energy .This engine works in cycle.In other words we can say that Heat engine is a device which covert thermal or chemical energy in to mechanical energy and after that this mechanical energy can be use for producing mechanical work.

Heat engine takes heat from high temperature and rejects heat to lower temperature and producing work.

We know that efficiency given as

\eta =\dfrac{out\ put}{in\ put}

From diagram we can say that

Q_1=Q_2+W

So efficiency

\eta =\dfrac{w}{Q_1}

\eta =\dfrac{Q_1-Q_2}{Q_1}

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A composite wall is to be used to insulate a freezer chamber at -350C. Two insulating materials are to be used with conductiviti
choli [55]

Answer:

thickness1=1.4m

thickness2=2.2m

convection coefficient=0.33W/m^2K

Explanation:

you must use this equation to calculate the thickness:

L=K(T2-T1)/Q

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T=temperature

Q=heat

L1=0.04*(0--350)/10=1.4m

L2=0.1(220-0)/10=2.2m

Then use this equation to calculate the convective coefficient

H=Q/(T2-T1)

H=10/(250-220)=0.33W/m^2K

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3 years ago
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Ierofanga [76]

...simplify devices, reducing weight and the chance of failure.

6 0
1 year ago
At 45° latitude, the gravitational acceleration as a function of elevation z above sea level is given by g = a − bz , where a =
Ahat [919]

Answer:

8861.75 m approximately 8862 m

Explanation:

We need to remember Newton's 2nd Law which says that the force experienced by an object is proportional to his acceleration and that the constant of proportionality between those two vectors correspond to the mass of the object.

F=ma for the weight of an object (which is a force) we have that the acceleration experienced by that object is equal to the gravitational acceleration, obtaining that  W = mg

For simplicity we work with g =9.807 \frac{m}{s^{2}} despiting the effect of the height above sea level. In this problem, we've been asked by the height above sea level that makes the weight of an object 0.30% more lighter.

In accord with the formula g = a-bz the "normal" or "standard" weight of an object is given by W = mg = ma when z = 0, so we need to find the value of z that makes W = m(a-bz) = 0.997ma meaning that the original weight decrease by a 0.30%, so now we operate...

m(a-bz) = 0.997ma now we group like terms on the same sides ma(1-0.997) = mbz we cancel equal tems on both sides and obtain that z = \frac{a}{b} (0.003) = \frac{9.807 \frac{m}{s^{2} } }{3.32*10^{-6} s^{-2} } (0.003) = 8861.75 m

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3 years ago
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lina2011 [118]

Answer:

Student A

Explanation:

hope this helps have a great day

4 0
3 years ago
Differnence between boat and ship​
Blababa [14]

Answer:

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3 years ago
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