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miss Akunina [59]
3 years ago
14

URGENT HELP !! The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively. How much ho

rizontal force would you need to apply to a 34.4 kg object to start it moving from rest?
Physics
1 answer:
IRISSAK [1]3 years ago
7 0

Answer:

43.83 N

Explanation:

Given that,

The mass of an object, m = 34.4 kg

The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively.

The force of static friction,

F_s=\mu_smg\\\\F_s=0.53\times 34.4\times 9.8\\\\F_s=178.67\ N

The force of kinetic friction,

F_k=\mu_kmg\\\\F_k=0.40\times 34.4\times 9.8\\\\F_k=134.84\ N

Net force acting on the object is :

F = 178.67-134.84

= 43.83  N

Hence, this is the required solution.

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Thats the third law______

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larisa86 [58]

Answer:

No, it does not.

Explanation:

According to the Law of Gravitation, something going down has more kinetic energy than something going up because it attracts pressure from around it when going down. When it goes up, it has less gravitational force and inertia also stops the ball from rolling upward. Therefore, without the amount of kinetic energy, it will not have the same amount of acceleration.

8 0
3 years ago
A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step
Crazy boy [7]
From laws of motion:

S = ( \frac{v + u}{2} ) \times t
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s


Substitute the values, hence:
S = ( \frac{0 + 36}{2} ) \times 6
S = (18) \times 6 \\  \\ S = 108m

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
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6 0
4 years ago
I need to know the independent variable, dependent variable, control, and the hypothesis.
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IV - The miracle grow (since this does not change based on the dv)
DV- The height of the plant (since it depends on how much/ wether miracle grow was added.)
Control- The control would be the plant without any miracle grow
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7 0
3 years ago
Putting a beaker of water in a microwave and turning it on for a minute or two will increase the temperature of the water. Descr
Jobisdone [24]

Answer:

The equipment to use is: a beaker, a fixed amount of water, a thermometer.

The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made

Explanation:

The design of an experiment is to place the beaker in the microwave, with a good amount of water (approximately ⅔ of its capacity) and turn it on for small periods of time, generally the minimum is 30 s, quickly open the microwave, place a thermometer or better yet an infrared thermometer to measure the temperature of the water; repeat this several times.

The advantage of the infrared thermometer is that it reduces the transfer of heat between the water and the thermometer.

The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made.

The equipment to use is: a beaker, a fixed amount of water, a thermometer.

The main precaution that must be taken is not to open the microwave while it is on.

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