Answer : The normal boiling point of ethanol will be, 
or 
Explanation :
The Clausius- Clapeyron equation is :
where,
= vapor pressure of ethanol at 
= 98.5 mmHg
= vapor pressure of ethanol at normal boiling point = 1 atm = 760 mmHg
= temperature of ethanol = 
= normal boiling point of ethanol = ?
= heat of vaporization = 39.3 kJ/mole = 39300 J/mole
R = universal constant = 8.314 J/K.mole
Now put all the given values in the above formula, we get:
Hence, the normal boiling point of ethanol will be, or
Im sorry about my answer a while ago.
answer: it will not be half empty ever. because any gas take all the space of the tank. molecules are everywhere they take so much space.
The volume is 100mL.
The mass is 1.5kg which is equal to 1500g.
Thus, the density is 1500g / 100mL which is 15g/mL.
Answer:
73.46839716589713698731965
Explanation:
<span>4 x 36 moles. of Phosporus and 10 x 36 of Oxygen. I hope this helps. (:</span>
