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kaheart [24]
2 years ago
14

A satellite travels with a constant speed |v| as it moves around a circle centered on the earth. How much work is done by the gr

avitational force F on the satellite after it travels half way around the earth in time t?
Physics
1 answer:
7nadin3 [17]2 years ago
3 0

Answer:

W = 0

Explanation:

As the satellite moves in a circle the force is perpendicular to the path, therefore the work that is defined by

      W = F. r = f r cos θ

Since the force and the radius are perpendicular, the angle θ = 90º and the cosine 90 = 0, therefore there is no work for the circular motion.

W = 0

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An object with a mass of 5kg accelerates at 2m/s2. How much force in Newtons(N) is needed to cause this to happen??
Reptile [31]

Answer: The formula of Newtons second law of motion is F=MA so therefore it would be written like this Force = Mass X Acceleration

F = 5 x 2

F = 10 N

6 0
3 years ago
Water flows through a 4.50-cm inside diameter pipe with a speed of 12.5 m/s. At a later position, the pipe has a 6.25-cm inside
jek_recluse [69]

Given,

The initial inside diameter of the pipe, d₁=4.50 cm=0.045 m

The initial speed of the water, v₁=12.5 m/s

The diameter of the pipe at a later position, d₂=6.25 cm=0.065 m

From the continuity equation,

\begin{gathered} A_1v_1=A_2v_2 \\ \pi(\frac{d_1}{2})^2v_1=\pi(\frac{d_2}{2})^2v_2 \\ \Rightarrow d^2_1v_1=d^2_2v_2 \end{gathered}

Where A₁ is the area of the cross-section at the initial position, A₂ is the area of the cross-section of the pipe at a later position, and v₂ is the flow rate of the water at the later position.

On substituting the known values,

\begin{gathered} 0.045^2\times12.5=0.065^2\times v_2 \\ \Rightarrow v_2=\frac{0.045^2\times12.5}{0.065^2} \\ =5.99\text{ m/s} \end{gathered}

Thus, the flow rate of the water at the later position is 5.99 m/s

4 0
1 year ago
A ball is pushed into a spring-loaded launcher with a force of 20 N, which compresses the spring 0.08 m.
damaskus [11]

Answer:

0.8J

Explanation:

Given parameters:

Force  = 20N

Compression  = 0.08m

Unknown:

Spring constant  = ?

Elastic potential energy  = ?

Solution:

To solve this problem, we use the expression below:

           F = k e

F is the force

k is the spring constant

e is the compression

             20  = k x 0.08

              k  = 250N/m

Elastic potential energy;

       EPE  = \frac{1}{2} k e²    =  \frac{1}{2}  x 250 x 0.08²

 Elastic potential energy = 0.8J

3 0
2 years ago
Help asap please I will give you 5stars
boyakko [2]

Explanation:

In the parallel combination, the equivalent resistance is given by :

\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+....

4. When three 150 ohms resistors are connected in parallel, the equivalent is given by :

\dfrac{1}{R}=\dfrac{1}{150}+\dfrac{1}{150}+\dfrac{1}{150}\\\\R=50\ \Omega

5. Three resistors of 20 ohms, 40 ohms and 100 ohms are connected in parallel, So,

\dfrac{1}{R}=\dfrac{1}{20}+\dfrac{1}{40}+\dfrac{1}{100}\\\\=11.76\ \Omega

Hence, this is the required solution.

6 0
3 years ago
Help help help HELP AAAAA
charle [14.2K]
The answer is B

As seen on the graph, the bus maintains a 9m/s speed for a majority of the trip to school.
5 0
3 years ago
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