To solve this problem we will apply the concepts related to electromagnetic force. This force is defined as the product between the free space permeability constant, the product of the two currents found, at the rate of the distance that separates them. In this way mathematically it can be given as,
Here,
= Permeability of free space
I = Each current
d = Distance
Replacing with our values,
Therefore the force is 
Answer:
12.5 m/s
Explanation:
In a acceleration time graph the area under the curve gives the change in velocity of the object. Here object starts at rest and therefore initial velocity is 0. After 5 seconds acceleration is 5m/s2.
change in velocity=area under the curve
change in velocity= 0.5*acceleration* change in time
v-0=0.5*5*5
v=12.5 m/s
Immediately following the arrival of the stimulus at a skeletal muscle cell, there is a short period called the latent period during which the events of excitation-contraction coupling occur.
This process is a connection between transduction in the sarcolemma and the initiation of muscle contraction. Sarcolemma is nothing but the cell membrane of skeletal muscle.
A single muscle twitch has a latent period, a contraction phase when tension increases and a relaxation phase when tension decreases.
The period of incubation, the interval preceding exposure to a pathogen toxin or radiation, and when effects occur. Muscle contracting, the time between a nerve stimulus and muscle contraction.
To know more about muscles:
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Answer: a. Regularly, you rub your hands for warmth.
b. Some examples are friction from electricity going through a wire or friction from rubbing your hand together.
c. Without friction, we would fall every time we walked. Because there is friction, we can walk normally. Another example is a ball moving across the field. Without friction, the ball would not slow down.
Explanation:
Overall, friction is important to us because we depend on it.
Answer:
(i)The current flow in black wire = 9.67 A (ii) The current low in the red wire is 9.68 A (iii) The current flow in neutral wire is 15.36 A (iv) when 240 volt were disconnected current in black wire is 7.68 A (v) when 240 volt were disconnected current in red wire is 7.68 A (vi) 15.36 A (vii) 6.34 (viii) 9.68 A (ix) 12.02 A
Explanation:
Solution
The current drawn by one amp is
I =P/V
I =200/120
I= 1.67 A
(i) The current flow in the black wire is
IBK = 4 * 1.67 A + 1A + 2A
IBK = 9.67 A
(ii) Current flow in the red wire is
IRD = 3 * 1.67 A + 1.67 A + 1A + 2A
= 8.68A + 1 A = 9.68 A
Note: Kindly find an attached copy of part of the solution to the given question above.
