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kaheart [24]
2 years ago
14

A satellite travels with a constant speed |v| as it moves around a circle centered on the earth. How much work is done by the gr

avitational force F on the satellite after it travels half way around the earth in time t?
Physics
1 answer:
7nadin3 [17]2 years ago
3 0

Answer:

W = 0

Explanation:

As the satellite moves in a circle the force is perpendicular to the path, therefore the work that is defined by

      W = F. r = f r cos θ

Since the force and the radius are perpendicular, the angle θ = 90º and the cosine 90 = 0, therefore there is no work for the circular motion.

W = 0

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Detailed Explanation:

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4Fe + 3O2 + 2H2O -> 2Fe2O32H2O

Reactants :-
Fe = 4
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Products :-
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C12H22O11 + H2O -> 4C2H5OH + 4CO2

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Products :-
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Looking closely at the way I have taken the total number of elements on the reactants and products side, you can solve the rest.

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2 years ago
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antiseptic1488 [7]

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Answer:

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