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4 years ago

What happens to the demand for butter, if the price of margarine increases? For Economics.

Physics

2 answers:

damaskus [11]4 years ago

8 0

People will buy more butter, and then eventually the margarine would lower and this cycle would keep repeating

Anastaziya [24]4 years ago

7 0

Supply and demand goes up .

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Q3. You throw a ball into the air, it reaches a certain height and then comes back to you.

Grace [21]

The If a car is going round a curve , there is an acceleration because the direction of the velocity changes.

<h3>What is the direction of the velocity?</h3>

Now we know that if you throw the ball upwards, the motion is in opposite direction to gravity thus the ball is experiencing deceleration and the speed decreases. The velocity decreases and the acceleration is negative.

If the ball is coming down, then the ball is accelerated thus it speeds up and the direction of the acceleration is positive.

If a car is going round a curve, the vehicle is accelerating because the direction of the velocity changes even if its amount remains constant.

When a board is moving down a hill at 2 ms-1, it is experiencing an acceleration because the motion is in the same direction as gravity.

If a car is coming to a stop at a point, it experiences a deceleration and not an acceleration since the change of velocity with time is negative as the car comes to rest.

Learn more about acceleration:brainly.com/question/12550364

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2 years ago

Moon problem please help!

Mariulka [41]

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4 0

3 years ago

Read 2 more answers

A novice pilot sets a plane’s controls, thinking the plane will fly at 2.50 × 102 km/h to the north. if the wind blows at 75 km/

serg [7]

Velocity of plane is given as

$v_1 = 2.50 * 10^2 km/h$ towards north

$v_2 = 75 km/h$ towards south east

we can write the two velocity in vector form

$v_1 = 2.50 * 10^2 \hat j$

$v_2 = 75 cos45 \hat i - 75 sin45 \hat j$

now the net velocity will be given as

$v_{net} = v_1 + v_2$

$v_{net} = 250\hat j + 53.03 \hat i - 53.03 \hat j$

$v_{net} = 53.03\hat i + 196.97 \hat j$

so the resultant velocity will be given as

$v_{net} = \sqrt{53.03^2 + 196.97^2}$

$v_{net} = 203.98 m/s$

and the angle of velocity will be

$\theta = tan^{-1}\frac{v_y}{v_x}$

$\theta = tan^{-1}\frac{196.97}{53.03} = 74.9 degree$

3 0

4 years ago

A ball with a mass of 0.585 kg is initially at rest. It is struck by a second ball having a mass of 0.420 kg , initially moving

Y_Kistochka [10]

Answer:

a) $(v_1)=0.3989m/s$

b) $\theta_1=80.5 \textdegree$

c) $K.E=0.036J$

Explanation:

From the question we are told that:

Initial speed of 1st ball $u_{1}=0 m/s$

Mass of 1st ball $m_1=0.585kg$

Mass of 2nd ball $m_2=0.420kg$

Initial speed of 2nd ball $u_{2}=0.270 m/s$

Final speed of 2nd ball $v_{2}=0.220 m/s$

Angle of collision $\angle=36.9 \textdegree$

Generally the equation for law of conservation is mathematically given by

$m_1u_1+m_2u_2=m_1v_1^2+m_2v_2^2$

The final velocity $v_1$ is given as

$0+(0.420)(0.270)=(0.585)(v_1)^2+(0.420)(0.220)^2$

$(v_1)^2=\frac{(0.420)(0.270)-(0.420)(0.220)^2}{0.585}$

$(v_1)^2=0.1591$

$(v_1)=0.3989m/s$

Generally the equation for law of conservation is mathematically given by

$m_1u_1+m_2u_2=m_1v_1cos\theta_1+m_2\theta_2$

$0+(0.420)(0.270)=(0.585)(1.511)cos\theta_1+(0.420)(0.220)cos36 \textdegree$

$cos\theta_1= \frac{(0.420)(0.270)-(0.420)(0.220)cos36 \textdegree}{(0.585)(0.3989)}$

$cos\theta_1=0.1656$

$\theta_1=80.5 \textdegree$

Generally the equation for kinetic energy is mathematically given by

$K.E=\frac{1}{2} mv^2$

1st Ball

$K.E=\frac{1}{2} (0.585)(0.3989)^2$

$K.E=0.0465J$

2nd ball

$K.E=\frac{1}{2} (0.420)(0.220)^2$

$K.E=0.101J$

Therefore the change in the total kinetic energy of the two balls as a result of the collision is

$0.101-0.0465$

$K.E=0.036J$

3 0

3 years ago

How much force is exerted if a 250 kg object has an acceleration of 750 m/s2 ?

Andrew [12]

Use Newton’s second law: F=ma
m= 250kg. a= 750ms-2
F= 250 x 750 = 187 500N

6 0

3 years ago

Read 2 more answers