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3 years ago

What happens to the demand for butter, if the price of margarine increases? For Economics.

Physics

2 answers:

damaskus [11]3 years ago

8 0

People will buy more butter, and then eventually the margarine would lower and this cycle would keep repeating

Anastaziya [24]3 years ago

7 0

Supply and demand goes up .

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An aircraft is in a steady climb, at an airspeed of 100 knots, and the flight path makes a positive 10 degree angle with the hor

kirill [66]

The rate of climb of the aircraft in a steady climb is : 17.36 knots

Given data

Airspeed = 100 knots

Angle with the horizontal ( ∅ ) = 10°

<h3>Determine the rate of climb of the aircraft </h3>

we will apply the formula below

Vy ( rate of climb ) = Airspeed * sin ∅

= 100 * sin ( 10 )

= 17.36 Knots

Hence we can conclude that rate of climb of the aircraft in a steady climb is : 17.36 knots.

Learn more about rate of climb : brainly.com/question/25573309

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2 years ago

You are lying on a beach, your eyes 20cm above the sand. Just as the Sun sets, fully disappearing over the horizon, you immediat

Naya [18.7K]

Answer:

The time is $t = 8.78 \ s$

Explanation:

From the question we are told that

The initial height of the eye is $h _1 = 20 \ cm = 0.2 \ m$

The height of the eye when you jumped up is $h_2 = 150 \ cm = 1.5 \ m$

An illustration of this question is shown on the first uploaded image

Generally the radius of the earth is $R = 6.38*10^{6} \ m$

Now from the diagram first sun means first time you saw the sun and the second sun means second time you saw the sun then

H is the height increase when you quickly stood up which is mathematically evaluated as

$H = h_2 -h_1$

$H = 1.5 - 0.2$

$H = 1.3 \ m$

Also $\theta$ i the angular displacement between the first and second position and from geometry it is also the angle at one of the sides of the right angle triangle

Applying Pythagoras theorem

$(R+H)^2 = K^2 + R^2$

=> $R^2 + H^2 + 2RH = K^2 + R^2$

Now given that H is very small compared to R the we ignore $H^2$

$R^2 + 2RH = K^2 + R^2$

=> $K = \sqrt{2RH}$

=> $K = \sqrt{2 * 6.38*10^6 * 1.3 }$

=> $K = 4073 \ m$

Now the $\theta$ is mathematically evaluated using SOHCAHTOA as follows

$tan \theta = \frac{K}{R}$

$\theta = tan^{-1}[ \frac{K}{R}]$

=> $\theta = tan^{-1}[ \frac{ 4073}{6.38*10^{6}}]$

=> $\theta = 0.0366^o$

Generally

$1 \revolution\ around \ the\ earth = 24 \ hours = 86400 \ seconds = 360 ^o$

$\frac{\theta}{360} = \frac{t}{86400}$

=> $\frac{0.0366}{360} = \frac{t}{86400}$

=> $t = 8.78 \ s$

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3 years ago

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Explanation:

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2 years ago

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Answer:

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2 years ago

The law of conservation of momentum states that the total momentum of interacting objects does not _____. This means the total m

drek231 [11]

Answer:

The law of conservation of momentum states that the total momentum of interacting objects does not change. This means the total momentum before a collision or explosion is equal to the total momentum after a collision or explosion.

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2 years ago

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