Answer:

Explanation:
Given:
- mass of solid disk,

- radius of disk,

- force of push applied to disk,

- distance of application of force from the center,

<em>For the condition of no slip the force of static friction must be greater than the applied force so that there is no skidding between the contact surfaces at the contact point.</em>

where:
= static frictional force




Weight is force.
The metric unit of force is the Newton.
1 Newton is the force needed to accelerate 1 kilogram at the rate of 1 m/s² .
The correct answer of this question is : 10.2 Kg.
EXPLANATION :
As per the question, the ball is attached to the cable.
The tension produced in the cable when the ball is hanged from it, is equal to the weight of the ball. It is so because the cable maintains its equilibrium.
Hence, tension in the cable = weight of the ball.
The tension produced in the cable is given as T = 100 N.
The weight of the ball is equal to the product of mass with acceleration due to gravity.
Let the mass of the ball is m.
Hence, weight of the ball W = mg
Here, g is known as acceleration due to gravity, and its value is g =
.
From above, we know that W = T
⇒ mg = 100 N
⇒ m =
Kg
= 
= 10.2 Kg. [ans]
Answer:
The three major parts of a cell are:
a. Cell membrane
b. Nucleus
c. Cytoplasm
Explanation:
a. Cell membrane:
It provides protection for a cell.
b. Nucleus:
It controls and regulates the activities of cell.
c. Cytoplasm:
It supports and suspends organelles and cellular molecules.