Question

Which nucleus completes the following equation?

Answer 1

Answer:

$_{84}^{208}Po$

B is correct.

Explanation:

Given the equation

$_{86}^{212}Rn\rightarrow_{2}^{4}He$

According to alpha emission

Alpha emission is a radioactive decay in which the atomic nucleus emit the alpha particle and formed a new nucleus whose mass number reduced by four and atomic number reduced by two.

Therefore,

Po is the new nucleus.

$_{86}^{212}Rn\rightarrow_{2}^{4}He+_{84}^{208}Po$

Where, Rn = Radon

Po= polonium

 

Answer 2

A is the answer I really don’t know the answer to that but if u can u can help me on my work