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Semmy [17]
3 years ago
14

A truck enters a typical runaway lane with a speed of 57.5 mph ( 25.7 m/s ). Use the work-energy theorem to find the minimum coe

fficient of kinetic friction between the truck and the lane to be able to stop the truck.
Physics
1 answer:
Helen [10]3 years ago
4 0

Answer:

Work done by friction force= change in total Energy

so,

W= (friction force)*d= (mu*N)*(35)

so,

mu*m*g*35= 1/2*m*v^2

so,

mu= 0.5*(25.7)^2/(9.81*35)

solving it,

mu = 0.9618

Explanation:

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goldenfox [79]

Answer:

Your answer is D It does not need to be repeatable.

the reason for this is because C is correct.

You need to be able to experiment on something multiple times so that you can gather further data to imbedded your evidence in facts.

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What is the kinetic energy of a 478 kg object that is moving with a speed of 15 m/s
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The Millennium Falcon was constructed 43.6 m long. a) How fast is it traveling past Luke when he measures its length to be 30.1
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Answer:

a)0.5564c

b)43.6 m

Explanation:

Given proper length of falcrum L₀= 43.6 m

improper length L=30.1 m (when viewed from moving frame)

we know that L=L_{0}\sqrt{1-\frac{v^2}{c^2}}

30.1=43.6\sqrt{1-\frac{v^2}{c^2}

⇒\{1-\frac{v^2}{c^2}}=\frac{30.1}{43.6}

{1-\frac{v^2}{c^2}}=0.6904

\frac{v^2}{c^2}=0.3096

v^{2}=3096c^{2}

v=0.5564c

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43.6 m

8 0
3 years ago
A model airplane of mass 0.6 kg is attached to a horizontal string and flies in a horizontal circle of radius 6 m, making 1.6 re
nikitadnepr [17]

Answer:

speed= 12.15\frac{m}{s}

Explanation:

In this question we have given

mass of airplane=.6 Kg

Radius of horizontal circle,r=6m

Time taken to complete 1.6 revolution=5s

Therefore time taken to complete 1 revolution, t=\frac{5}{1.6}

t=3.1 s

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We will first find the distance covered by airplane in tracing one circle which is equal to circumference of circle

We know that

Circumference,d = 2 \pi \times r

or d=2\times 3.14 \times 6

d=37.68 m

We know that speed=\frac{d}{t}............(1)

Put value of d and t in equation 1

speed=\frac{37.68}{3.1}

speed= 12.15\frac{m}{s}

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