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Travka [436]
3 years ago
12

Gravity is not considered matter. A. True B. False​

Physics
1 answer:
Strike441 [17]3 years ago
7 0

Answer:

false gravity is not considered matter

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The speed of the proton when it reaches point
romanna [79]
1) An electron is moving east in a uniform electric field of 1.53N/C directed to the west. At point A, the velocity of the electron is 4.51�105m/s pointed toward the east. What is the speed of the electron when it reaches point B, which is a distance of 0.400m east of point A? 2) A proton is moving in the uniform electric field of part A. At point A, the velocity
8 0
3 years ago
Hi, so i have to find T1, can some1 help?
iragen [17]

30.1 N

Explanation:

Given:

W_1 = 16\:\text{N}

W_2 = 8\:\text{N}

Let's write the components of the net forces at the intersections. Note that the system is equilibrium so all the net forces are zero.

<u>Forces</u><u> </u><u>involving</u><u> </u><u>W1</u><u>:</u>

x:\:\:\:-T_1 + T_3\cos \alpha = 0\:\: \\ \text{or}\:\:T_2 = T_3\cos \alpha\:\:\:\:\:(1)

y:\:\:\:T_3\sin \alpha - W_1 = 0\:\:\: \\ \text{or}\:\:\:T_3\sin \alpha = W_1\:\:\:\:\:\:(2)

<u>Forces</u><u> </u><u>involving</u><u> </u><u>W2</u><u>:</u>

x:\:\:\:T_1\sin 53 - T_3\sin \alpha = W_2\:\:\:\:\:\:\:(3)

y:\:\:\:T_4 - T_1\cos 53 - T_3\cos \alpha = 0\:\:\:\;(4)

Substitute (2) into (3) and we get

T_1\sin 53 - W_1 = W_2

Solving for T_1,

T_1 = \dfrac{W_1 + W_2}{\sin 53} = 30.1\:\text{N}

7 0
3 years ago
An electromagnetic wave in a vacuum has a wavelength of 0.032 m. What is its frequency?
Sergio [31]
L=wavelength
L=0.032
c=Lf
f=c/L
f=3e8/0.032
f=9.375GHz
7 0
3 years ago
A droplet of ink in an industrial ink-jet printer carries a charge of 1.6 x 10–11 coulombs and is deflected onto paper by a forc
Novosadov [1.4K]

Answer:

<em>The Strength of the electric field produced =  2 × 10⁷ N/C</em>

Explanation:

<em>Electric Field:</em> This is defined as the region where an electric force is experienced.

<em>Electric Field Strength: </em><em>The intensity of an electric field at any point is defined as the force per unit charge which it exert at that point. It direction is that of  the force exerted on a positive charge.</em>

<em>It is represented mathematically as,</em>

<em>E = F/Q ................................. Equation 1</em>

<em>Where E = Electric field strength, F = electric force, Q = test charge.</em>

<em>Given: F = 3.2 × 10⁻⁴ N, Q = 1.6 × 10⁻¹¹ C</em>

<em>Substituting these values into equation 1</em>

<em>E= 3.2 × 10⁻⁴/1.6 × 10⁻¹¹ </em>

<em>E= 2 × 10⁷ N/C</em>

<em>Thus the Strength of the electric field produced =  2 × 10⁷ N/C</em>

<em />

3 0
3 years ago
The net external force acting on an object is zero. Is it possible for the object to be traveling with a velocity that is not ze
Rzqust [24]

Answer:

Yes, this is according to the Newton's first law of motion.

Neither its direction nor its velocity changes during this course of motion.

Explanation:

Yes, it is very well in accordance with Newton's first law of motion for a body with no force acting on it and it travels with a non-zero velocity.

During such a condition the object will have a constant velocity in a certain direction throughout its motion. Neither its direction nor its velocity changes during this course of motion.

4 0
3 years ago
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