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3 years ago

Which equation should be used to calculate the heat change when a given molar amount of H2O is heated from 15oC to 95oC

Chemistry

1 answer:

KIM [24]3 years ago

5 0

Answer:

q = m x Cp x ΔT

Explanation:

In the range of temperatures from 15°C to 95°C, water is in the liquid phase. So, the heating process is <u><em>within the liquid phase</em></u> and does not involve a change of phase. Therefore, the equation used to calculate the heat absorbed (q) is:

q = m x Cp x ΔT

Where m is the mass of water, Cp is the specific heat of water and ΔT is the change of temperature (in this case: 95°C - 15°C = 80°C).

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Fructose-2,6-bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolys

postnew [5]

Answer:

1. Increased levels of fructose-2,6-bisphosphatase : Activate gluconeogenesis Inhibit glycolysis

2. Activation of fructose-2,6-bisphosphate (FBPase-2) : Activate glycolysis Inhibit gluconeogenesis

3. Increased glucagon levels : Activate gluconeogenesis Inhibit glycolysis

4. Activation of PFK-2 : Activate glycolysis Inhibit gluconeogenesis

5. Increased levels of CAMP : Activate gluconeogenesis Inhibit glycolysis

Explanation:

Glycolysis is the breakdown of glucose molecules in order to release energy in the form of ATP in response to the energy needs of the cells of an organism.

Gluconeogenesis is the process by which cells make glucose from other molecules for other metabolic needs of the cell other than energy production.

Glycolysis and gluconeogenesis are metabolically regulated in the cell by various enzymes and molecules.

The following shows the various regulatory methods and their effects on both processes:

1. The enzyme fructose-2,6-bisphosphatase functions in the regulation of both processes. It catalyzes the breakdown of the molecule fructose-2,6-bisphosphate which is an allosteric effector of two enzymes phosphofructokinasse-1, PFK-1 and fructose-1,6-bisphosphatase, FBPase-1 which fuction in glycolysis and gluconeogenesis respectively.

Increased levels of fructose-2,6-bisphosphatase activates gluconeogenesis and inhibits glycolysis by its breakdown of fructose-2,6-bisphosphate.

2. Fructose-2,6-bisphosphate increases the activity of PFK-1 and inhibits the the activity of FBPase-1. The effect is that glycolysis is activated while gluconeogenesis is inhibited.

3. Glucagon is a hormone that stimulates the synthesis of cAMP. It fuctions to activate gluconeogenesis and inhibit glycolysis.

4. Phosphosfructikinase-2, PFK-2 is an enzyme that catalyzes the formation of fructose-2,6-bisphosphate. Activation of PFK-2 results the activation of glycolysis and inhibition of gluconeogenesis.

5. Cyclic-AMP (cAMP) synthesis in response to glucagon release serves to activate a cAMP-dependent protein kinase which phosphorylates the bifunctional protein PFK-2/FBPase-2. This phosphorylation enhances the activity of FBPase-2 while inhibiting the activity of PFK-2, resulting in the activation of gluconeogenesis and inhibition of glycolysis.

7 0

3 years ago

In the background information, it was stated that CaF2 has solubility, at room temperature, of 0.00160 g per 100 g of water. How

____ [38]

Answer:

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

Explanation:

First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:

Ca: 40 g/mole
F: 19 g/mole

So the molar mass of CaF₂ is:

CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

$moles=\frac{0.0016 grams*1 mole}{78 grams}$

moles=2.05*10⁻⁵

<u><em>2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.</em></u>

Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

$mass of CaF_{2}=\frac{1000 mL*1g}{1mL}$

mass of CaF₂= 1000 g

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

$moles=\frac{1000 grams*1 mole}{78 grams}$

moles=12.82

<u><em>12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution</em></u>

5 0

3 years ago

Which regions of the world seem to be suffering most from loss of species ?

Lana71 [14]

Answer:

The most dangerous area for animals and plants is the one that contains the greatest biodiversity on the planet: Southeast Asia. In this region are the five most affected countries in the world: Malaysia, Brunei, Singapore, Indonesia and Thailand. The Atlantic rainforests of Brazil are also very affected, this is due to the fact that great catastrophes have occurred in these places lately, such as the massive fire in the Amazon, and the floods that occurred after the tremendous absence of vegetation that these places suffered.

Explanation:

Also on the other hand, the regions with the highest extinction are those that carry out little environmental policies where care has not been taken for species that are in danger of extinction, as happens, for example, in those islands such as the Galapagos Islands, which are subject to severe fines for harm turtles.

3 0

3 years ago

What is the frequency of electromagnetic radiation with a wavelength of 6.34 x 10^8 m?

Svetllana [295]

<h2>Answer: 4.72 × 10⁷ s⁻¹ or Hz</h2><h3> Explanation: </h3>

frequency = speed of light ÷ wavelength

frequency = (2.99 × 10⁸ m/s) ÷ (6.34 × 10⁸ m)

= 4.72 × 10⁷ s⁻¹ or Hz

8 0

3 years ago

Identify oxidation. Group of answer choices loss of electrons loss of electron or an increase in oxidation number gain of proton

STatiana [176]

Explanation:

loss of electron or an increase in oxidation number

4 0

3 years ago