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3 years ago

10

What is the pH of the 1.0 M KOH solution?

2 answers:

Vadim26 [7]3 years ago

4 0

So pH of the 1.0 * 10-2 mol-1 KOH is 12.

kumpel [21]3 years ago

4 0

Answer:

<h3> So... pH of the 1.0" 10-2 mol-1 KOH is..</h3>

<h2> = <u>1</u><u>2</u></h2>

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Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou

Ulleksa [173]

Answer:

$4.36~g~XY$

Explanation:

In this case, we can start with the reaction:

$2X + Y_2~->~2XY$

If we check the reaction, we will have 2 X and Y atoms on both sides. So, <u>the reaction is balanced</u>. Now, the problem give to us two amounts of reagents. Therefore, we have to find the <u>limiting reagent</u>. The first step then is to find the moles of each compound using the <u>molar mass</u>:

$3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X$

$4.2~g~Y_2\frac{1~mol~Y_2}{48~g~Y_2}=0.0875~mol~Y_2$

Now, we can <u>divide by the coefficient</u> of each compound (given by the balanced reaction):

$\frac{0.04~mol~X}{1}=~0.04$

$\frac{0.0875~mol~Y_2}{2}=0.04375$

The smallest value is for "X", therefore this is our <u>limiting reagent</u>. Now, if we use the <u>molar ratio</u> between "X" and "XY" we can calculate the moles of XY, so:

$0.04~mol~X\frac{2~mol~XY}{2~mol~X}=0.04~mol~XY$

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol $Y_2$ = 48 g $Y_2$ (therefore 1 mol Y = 24 g Y). With this in mind the <u>molar mass of XY</u> would be 85+24 = 109 g/mol. With this in mind:

$0.04~mol~XY\frac{109~g~XY}{1~mol~XY}=4.36~g~XY$

I hope it helps!

6 0

3 years ago

The rate of geologic processes can happen quickly or take a long time.

erik [133]

Answer:

Take a long time

Explanation:

Geology is defined as a science mostly concerned with the study of the history of the earth as recorded in different rocks formations.

Geologic processes are events that occur on a geological timescale which may span across many centuries.

The four major geologic process are known to include; impact cratering, volcanism, tectonics, and erosion.

7 0

3 years ago

While doing a lab a student found the density of a piece of pure aluminum to be 2.85 g/cm3 the accepted value for the density of

____ [38]

Answer:

THE PERCENT ERROR IS 5.55 %

Explanation:

To calculate the percent error, we use the formula:

Percent error = Found value - accepted value / accepted value * 100

Found value = 2.85 g/cm3

Accepted value = 2.70 g/cm3

Solving for the percent error, we have:

Percent error = 2.85 g/cm3 - 2.70 g/cm3 / 2.70 g/cm3 * 100

Percent error = 0.15 / 2.70 * 100

Percent error = 0.05555 * 100

Percent error = 5.55 %

In conclusion, the percent error is 5.55 %

3 0

3 years ago

What amount of heat is released when the temperature of 450.0 g of a

Molodets [167]

Answer:

$\boxed {\boxed {\sf 4038.48 \ Joules}}$

Explanation:

Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:

$q=mc\Delta T$

The substance's mass is 450.0 grams, the specific heat is 1.264 J/g°C, and the change in temperature is 7.1 °C.

$m= 450.0 \ g \\c= 1.264 \ J/g \textdegree C\\\Delta T= 7.1 \ \textdegree C$

Substitute the values into the formula.

$q= (450.0 \ g)(1.264 \ J/g \textdegree C)(7.1 \ \textdegree C)$

Multiply the first 2 values together. The grams will cancel out.

$q= 568.8 \ J/ \textdegree C (7.1 \ \textdegree C)$

Multiply again. This time, the degrees Celsius cancel out.

$q= 4038.48 \ J$

<u>4038.48 Joules</u> of heat energy are released.

5 0

3 years ago

What is the current model of atom

leonid [27]

Answer:

The bohr model is the model in use today

7 0

2 years ago