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sukhopar [10]
3 years ago
15

What is the potential energy for 65kg climber on top of Mount Everest (8,800 m high)

Physics
1 answer:
Fed [463]3 years ago
6 0

Answer:

PE= m * g *h

work:

PE= 65kg * 9.8 kg *8,800 m

PE=5605600 m/kg

idk the actual units i forgot

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describe the relationship between the direction of the velocity vector and the direction of the acceleration for a body moving i
Xelga [282]

Answer:

a = v²/r

Explanation:

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a = v²/r where

v is the linear velocity

r is the radius

a is the centripetal acceleration

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How many protons are in the radioactive isotope 40/19K?
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First we have to establish that the number of protons is equivalent to the atomic number of element. Here I am assuming that you are referring to Potassium (K) - 40. Potassium, stable or unstable has 19 protons.
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Read 2 more answers
A father racing his son has 1/3 the kinetic energy of the son, who has 1/4 the mass of the father. The father speeds up by 1.5 m
Feliz [49]

Explanation:

Let the speeds of father and son are v_f\ and\ v_s. The kinetic energies of father and son are K_f\ and\ K_s. The mass of father and son are  m_f\ and\ m_s

(a) According to given conditions, K_f=\dfrac{1}{3}K_s

And m_s=\dfrac{1}{4}m_f

Kinetic energy of father is given by :

K_f=\dfrac{1}{2}m_fv_f^2.............(1)

Kinetic energy of son is given by :

K_s=\dfrac{1}{2}m_sv_s^2...........(2)

From equation (1), (2) we get :

\dfrac{v_f^2}{v_s^2}=\dfrac{1}{12}..............(3)

If the speed of father is speed up by 1.5 m/s, so the ratio of kinetic energies is given by :

\dfrac{K_f}{K_s}=\dfrac{1/2m_f(v_f+1.5)^2}{1/2m_sv_s^2}

v_s^2=4(v_f+1.5)^2

Using equation (3) in above equation, we get :

v_f=\dfrac{1.5}{\sqrt3-1}=2.04\ m/s

(b) Put the value of v_f in equation (3) as :

v_s=7.09\ m/s

Hence, this is the required solution.

8 0
3 years ago
the mass of one water drop is 0.0008kg and the gravitational field strength is 10N/kg what is its weight
djyliett [7]
Weight = (mass) x (gravity)

Weight = (8 x 10⁻⁴ kg) x (10 N/kg) = 0.008 Newton
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