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3 years ago

Convert 6.62 X 10^23 atoms to moles

Chemistry

2 answers:

olga2289 [7]3 years ago

5 0

Answer:

1.099

Explanation:

Hope this helps

KengaRu [80]3 years ago

4 0

Answer:

1.09944660051578e-23

Explanation:

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Problem 3.100 a chemical plant uses electrical energy to decompose aqueous solutions of nacl to give cl2,h2, and naoh: 2nacl(aq)

chubhunter [2.5K]

First we calculate the number of moles of Cl2, that is:

moles Cl2 = 1.5*10^10 grams/71 grams/mol = 211267605.633802817 mol = 2.1 * 10 ^ 8 mole = x 

So that based on stoichiometry, the number of moles of NaOH = 2x and that of H2 = x mol

mass of NaOH = 4.2*10^8 * 40 =168*10^8 grams = 1.68 * 10^6 kg = 1.68 metric tons

mass of H2 = 2.1*10^8 * 2 = 4.2*10^8 grams = 0.042 * 10^6 kg = 0.042 metric tons.

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3 years ago

Complete the sentence using oxalate, oxic or oxide

Hitman42 [59]

Answer: oxide

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3 years ago

Which statement is true for balanced chemical equations? A) Chemical equations do not provide an accurate way of describing reac

zavuch27 [327]

E) is the correct answer

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3 years ago

Read 2 more answers

The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.

atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M

Explanation:

The photodissociation of ozone by UV light is given by:

O₃ + hν → O₂ + O (1)

The first-order reaction of the equation (1) is:

$rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t}$ (2)

where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration

We can get the following expression of the first-order integrated law of the reaction (1), by resolving the equation (2):

$[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt}$ (3)

where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration

We can calculate the initial ozone concentration using equation (3):

$[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M$

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!

3 0

4 years ago

What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough

olga55 [171]

Answer:

Explanation:

molar mass of BaCl2 = 208.23

mol of BaCl2 = 8/208.22

mol of BaCl2 = 0.03841905

Molarity = 0.03841905/0.450

Molarity = 0.085 M

6 0

2 years ago