The scientist could B) do an experiment to that would apply to only one of the theories.
If the results agreed with that theory, it would <em>become more acceptable</em>.
If the results disagreed with that theory, it would be <em>disproved</em> and the other theory would become more acceptable.
<h3><u>Answer</u>;</h3>
No, a precipitate does not form
<h3><u>Explanation</u>;</h3>
- Precipitation involves mixing or combining solutions that contain soluble ionic compounds to form an insoluble ionic compound by a reaction.
- Sodium acetate and ammonium sulfate are both soluble ionic compounds, which implies that they exist as ions in aqueous solution.
- <em><u>When they combine they form NH4CH3COOH and sodium sulfate, Na2SO4, which are both soluble salts, as all salts of ammonium and sodium are soluble.</u></em>
- <em><u>Both ammonium acetate and sodium sulfate are soluble because there are no anions that can form an insoluble solid with NH4+ and Na+ cations. </u></em>
Answer:
109.34 g
Explanation:
2NaOH(aq) + H2SO4(aq) ------> Na2SO4(aq) + 2H2O(l)
Number of moles of NaOH = 105g/40g/mol = 2.6 moles
From the reaction equation;
2 moles of NaOH yields 1 mole of sodium sulphate
2.6 moles of NaOH yields = 2.6 × 1/2 = 1.3 moles of sodium sulphate
Number of moles of H2SO4= 75.5g/98 g/mol = 0.77 moles
From the reaction equation;
1 mole of H2SO4 yields 1 mole of sodium sulphate
Hence, 0.77 moles of H2SO4 yields 0.77 moles of sodium sulphate
So H2SO4 is the limiting reactant.
Theoretical yield = number of moles × molar mass
= 0.77 mol ×142 g/mol
= 109.34 g
