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ololo11 [35]
3 years ago
9

Q.1 Newton's second law gives the measure of--------------. 1)Acceleration 2) Force 3) Momentum 4)Angular momentum​

Physics
1 answer:
posledela3 years ago
4 0

Answer:

1. Acceleration

Explanation:

Newtons Second law gives the measure of acceleration

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Which one is an accurate description of the process of erosion?
AURORKA [14]
The accurate description of the process of erosion is when <span>moving bits of rock and soil across the earth’s surface by water, wind, or glaciers. The answer is letter C.</span>
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3 years ago
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Find the difference between two masses measured as 123.6 grams and 115.972 grams. Express the answer to the correct number of si
xxTIMURxx [149]

Answer:

The difference is 7.6 grams.

Explanation:

In mathematics the difference of two numbers is express as the subtraction between them:

         

a-b

So to find out the difference between the two measured masses, a will be represented by 123.6 grams since is the bigger number, and b by 115.972 grams.

Therefore, it is get:

123.6grams-115.972grams = 7.6grams

<u>Hence, the difference is 7.6 grams. </u>

The result of 7.628 will be expressed as 7.6 to have the correct number of significant figures.          

 

Notice how that can be express in units of kilograms too since there is 1000 gram in 1 kilogram:

7.6grams . \frac{1Kg}{1000grams} ⇒ 7.6x10^{-3}Kg

8 0
3 years ago
A converging lens can produce both real and virtual images depending on the position of the object. Explain when converging lens
inessss [21]

Answer: C

Explanation:

5 0
3 years ago
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__________ enable humans to see and detect the color of different objects.
Llana [10]
The correct answer is C.
6 0
4 years ago
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n an experiment of a simple pendulum, measurements show that the pendulum has length m, mass kg, and period s. Take m/s2 . i. Us
barxatty [35]

Answer:

The answer is "(1.265 \pm 0.010) \ s \ and \ 0.709 \%"

Explanation:

In point i:

T_{theo}= 2\pi \sqrt{\frac{l}{g}}

        =2\pi\sqrt{\frac{0.397}{9.8}}\\\\= 1.265 \ s

If  error in the theoretical time period :

\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2}  \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}

           = 0.010 \ s

 T_{theo} = (1.265 \pm 0.010) \ s

In point ii:

\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100

<h3>                     = \frac{1.274 -1.265}{\frac{1.274+1.265}{2}} \times 100\\\\=0.709 \%</h3>
5 0
3 years ago
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