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3 years ago

What will the momentum of 23 kg object if it is travelling 5 m/s?

Physics

1 answer:

sasho [114]3 years ago

4 0

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 23 × 5

We have the final answer as

Hope this helps you

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An arch carries the thrust of weight to its _____(1)______. With a _____(2)______, the horizontal part of the structure supports

ivolga24 [154]

<h2>Arch Carries the thrust of Weight - Option D</h2>

An arch carries the thrust of weight to its sides. With a post-and-lintel, the horizontal part of the structure supports all the weight above it. The reason is that the post and lintel is a system of construction. In this the powerful parallel components are kept up by powerful upward components that has large cavities between them.

Therefore, an arch carries the thrust of weight to its sides for balancing purposes.

8 0

3 years ago

Read 2 more answers

a battery of 9v is connected in series with resistors of 0.2ohm , 0.3ohm, 0.5ohm, and 5 ohm respectively. how much current would

Nonamiya [84]

Answer:

1.5 A

Explanation:

Applying

V = IR'....................... Equation 1

make I the subject of the equation

I = V/R'.................. Equation 2

Where V = Voltage, I = current, R' = Total resistance.

From the question,

In a series connection,

R' = 0.2+0.3+0.5+5 = 6 ohm.

Given: V = 9V

Substitute into equation 2

I = 9/6

I = 1.5 A.

Note: Since all the resistors are connected in series, thesame current flows through them

Therefore the current flowing through the 5 ohm resistor = 1.5 A

5 0

3 years ago

How and why does breathing rate increase during exercise

kondor19780726 [428]

<span>Your heart speeds up to pump extra food and oxygen to the muscles. Breathing speeds up to get more oxygen and to get rid of more carbon dioxide. When a fit person, such as an athlete, exercises the pulse rate, breathing rate and lactic acid levels rise much less than they do in an unfit person.
</span>

7 0

4 years ago

At what height from the surface of the earth does the value of acceleration due to gravity be 2.45 m/s square where the radius o

Citrus2011 [14]

Answer:

Explanation: RADIUS OF EARTH = 6400X1000m =

ACC DUE GRAVITY ABOVE SURFACE OF EARTH = g' =2.45 m/s^2

ACC DUE GRAVITY ON SURFACE OF EARTH =g= 9.8 m/s^2

A/C TO FORmULA

g'/g=1-2h/Re

g'/g +2h/Re = 1

2h/Re =1- g'/g

2h= (1- g'/g)Re

2h=(1-2.45 /9.8)

6400X1000

2h = (0.75)6400X1000

2h = 4800000

h= 2400000

3 0

2 years ago

A particle of charge +2q is placed at the origin and particle of charge -q is placed on the x-axis at x = 2a. Where on the x-axi

zzz [600]

Answer:

$r_{31}=\frac{2a\sqrt{2}}{1+\sqrt{2}}$

Explanation:

We know that the electric force equation is:

$F=k\frac{q_{1}*q_{2}}{r^{2}}$

k is the electric constant $9*10^{9} Nm^{2}/C^{2}$
r is the distance between the particles
q1 and q2 are the particle

Now, we have three particles, the first one at x=0, the second one at x=2a and the third in some place between these two particle.

1. Let's find the electric force between the first particle and the third particle.

$F_{31}=k\frac{q_{3}*q_{1}}{r_{31}^{2}}$

$F_{31}=k\frac{q*2q}{r_{31}^{2}}$

$F_{31}=k\frac{2q^{2}}{r_{31}^{2}}$

r(31) is the distance between 3 and 1

2. Now, let's find the electric force between the third particle and the second particle.

$F_{32}=k\frac{q_{3}*q_{2}}{x_{32}^{2}}$

$F_{32}=k\frac{q*(-q)}{r_{32}^{2}}$

$F_{32}=-k\frac{q^{2}}{r_{32}^{2}}$

r(32) is the distance between 3 and 2.

Now, $r_{31}+r_{32}=2a$ or $r_{32}=2a-r_{31}$

The net force must be zero so:

$F_{31}+F_{32}=0[\tex][tex]k\frac{2q^{2}}{r_{31}^{2}}-k\frac{q^{2}}{r_{32}^{2}}=0[\tex] [tex]kq^{2}(\frac{2}{r_{31}^{2}}-\frac{1}{r_{32}^{2}})=0[\tex] [tex]kq^{2}(\frac{2}{r_{31}^{2}}-\frac{1}{(2a-r_{31})^{2}})=0[\tex] It means that:[tex]\frac{2}{r_{31}^{2}}-\frac{1}{(2a-r_{31})^{2}}$

We just need to solve it for r(31)

$r_{31}^{2}=2(2a-r_{31})^{2}$

$r_{31}=\frac{2a\sqrt{2}}{1+\sqrt{2}}$

Therefore the distance from the origin will be:

$r_{31}=\frac{2a\sqrt{2}}{1+\sqrt{2}}$

I hope it helps you!

4 0

4 years ago