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3 years ago

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Physics

1 answer:

Luda [366]3 years ago

3 0

Answer:

1) The change in momentum of the ball is 8 kgm/s

2) The total momentum of the bodies is 20 kgm/s

Explanation:

Given;

mass of the ball, m = 2 kg

initial velocity of the ball, v₁ = 2 m/s

final velocity of the ball, v₂ = -2 m/s (the ball rebounds)

The change in momentum of the ball is given by;

ΔP = Δmv

ΔP = mv₁ - mv₂

ΔP = m(v₁ - v₂)

ΔP = 2(2 - (-2))

ΔP = 2(2 + 2)

ΔP = 8 kgm/s

Given;

mass of the first body, m₁ = 5kg

mass of the second body, m₂ = 5kg

speed of the first body, v₁ = 2 m/s

speed of the second body, v₂ = 2 m/s

The total momentum of the bodies is given by

P = m₁v₁ + m₂v₂

P = (5 x 2) + (5 x 2)

P = 20 kgm/s

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moment before collision $=$ moment after collision

Third Trial

$mu_1+mu_2=mv_1+mv_2\\1(2)+1(1)=1(1)+1(-2)\\2+1=1-2\\3=-1$

momentum before collision $\neq$ moment after collision

Fourth Trial

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