Answer:
1) The change in momentum of the ball is 8 kgm/s
2) The total momentum of the bodies is 20 kgm/s
Explanation:
1)
Given;
mass of the ball, m = 2 kg
initial velocity of the ball, v₁ = 2 m/s
final velocity of the ball, v₂ = -2 m/s (the ball rebounds)
The change in momentum of the ball is given by;
ΔP = Δmv
ΔP = mv₁ - mv₂
ΔP = m(v₁ - v₂)
ΔP = 2(2 - (-2))
ΔP = 2(2 + 2)
ΔP = 8 kgm/s
2)
Given;
mass of the first body, m₁ = 5kg
mass of the second body, m₂ = 5kg
speed of the first body, v₁ = 2 m/s
speed of the second body, v₂ = 2 m/s
The total momentum of the bodies is given by
P = m₁v₁ + m₂v₂
P = (5 x 2) + (5 x 2)
P = 20 kgm/s
