A 20 kg object is dropped from a very tall building. What is the weight of this objects? After 5 seconds, how has the object fal
1 answer:
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Answer
given,
Mass of the runner, M = 70 Kg
speed of the runner on the second base = 4.35 m/s
speed at the base = 0 m/s
Acceleration due to gravity,g = 9.8 m/s²
a) magnitude of mechanical energy lost
Mechanical energy lost is equal top gain in kinetic energy
b) Work done = Force x displacement
W = F. x
F = μ mg
W = μ mg . x
Work done is equal to 662.29 J
using the coefficient of the friction,μ = 0.7
x = 1.38 m
Hence, the runner will slide to 1.38 m.
Answer:
(a) With a short line, the A,B,C,D parameters are:
A = 1pu B = 1.685∠60.8°Ω C = 0 S D = 1 pu
(b) The sending-end voltage for 0.9 lagging power factor is 35.96
(c) The sending-end voltage for 0.9 leading power factor is 33.40
Explanation:
(a)
Considering the short transition line diagram.
Apply kirchoff's voltage law to the short transmission line.
Write the equation showing the relations between the sending end and the receiving end quantities.
Compare the line equations with the A,B,C,D parameter equations.
(b)
Determine the receiving-end current for 0.9 lagging power factor.
Determine the line-to-neutral receiving end voltage.
Determine the sending end voltage of the short transition line.
Determine the line-to-line sending end voltage which is the sending end voltage.
(c)
Determine the receiving-end current for 0.9 leading power factor.
Determine the sending-end voltage of the short transition line.
Determine the line-to-line sending end voltage which is the sending end voltage.
