Answer:
Mg= 1.3418 kg*m/s
Explanation:
Mass of rifle

Recoil velocity of rifle

Momentum of rifle

mass of bullet
mb=7.2x10^{-3} kg=0.0072 kg
velocity of bullet relative to muzzel
v_{b} = 601 m/s
velocity of bullet relative to earth= 601 - 1.95=599.05 m/s
momentum of bullet

the momentum of the propellant gases = momentum of rifle - momentum of bullet
the momentum of the propellant gases
Mg=5.655 -4.3132
Mg= 1.3418 kg*m/s
the momentum of the propellant gases in a coordinate system attached to the earth as they leave the muzzle of the rifle is 1.3418 kgm/s
Answer:
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Explanation:
I live in a temperate biome
The churning air in the troposphere helps determine the altitude of a place
Answer: I don’t know the answer to this but just do what i do look up the question I’m sure someone has answered this hope it helps❤️
Explanation: