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Aloiza [94]
2 years ago
10

Can someone please check my answer?

Chemistry
1 answer:
Luden [163]2 years ago
4 0

Yes the ANSWER is Correct-

On first half life the mass will be 10 gram

On second half life the mass will be 5 gram

On third half life the mass will be 2.5 gram

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If an object has a volume of 2 millimeters and a mass of 10 grams, calculate the density of the object. (4 points)
kow [346]
Density = g/mL

10 g / 2 mL = 5 g/mL


3 0
3 years ago
A radioactive nuclide is used to detect eye tumors. An atom of this radionuclide contains 15 protons, 15 electrons, and
statuscvo [17]

Answer: ³²P

Explanation:

The radionuclide in question is known as Phosphorus-32. It is an isotope of Phosphorus that is radioactive and has one more neutron than the normal phosphorus does.

Phosphorus does not exist in nature and is created artificially by bombarding the normal stable phosphorus with neutrons. Due to its radioactive nature, it has proven to be useful in the medical industry where it has been used to detect eye tumors as well as in treating some diseases.

4 0
3 years ago
A bomb calorimetric experiment was run to determine the enthalpy of combustion of ethanol. The reaction is The bomb had a heat c
gulaghasi [49]

Answer:

The enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

Explanation:

The heat absorbed by the bomb and water is equal to the product of the heat  capacity and the temperature change. Working with this equation, and assuming no heat is lost to  the surroundings, we write :

qcal= Ccal × ΔT= 490 J/K × 276.7 K= <u>135,583 J</u> = 135.58 kJ

Note we expressed the temperature change in K, because the heat capacity is written in K.

<u> Now that we have the heat of combustion, we need to calculate the molar heat.  </u>

Because qsystem = qrxn + qcal and qrxn = -qcal, the heat change of the reaction is -135.58 kJ.

This is the heat released by the combustion of 4.40 g of ethanol ; therefore, we can write  the <u>conversion factor as 135.58 kJ/ 4.40 g</u>.

The molar mass of ethanol is 46.07 g, so the heat of combustion of 1 mole of ethanol is :

molar heat of combustion= -135.58 kJ/4.40 g x 46.07 g/ 1 mol= -1419.58 kJ/mol

Therefore, the enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

3 0
3 years ago
A sugar crystal contains approximately 1.4×1017 sucrose (C12H22O11) molecules. What is its mass in milligrams? Express using 2 s
alekssr [168]

Answer:

From the periodic table:

mass of carbon = 12 grams

mass of hydrogen = 1 grams

mass of oxygen = 16 grams

molar mass of surcose = 12(12) + 22(1) + 11(16) = 342 grams

number of molecules = number of moles x Avogadro's number

number of moles = number of molecules / Avogadro's number

number of moles = (2.2x10^17) / (6.02x10^23) = 3.6544 x 10^-7 moles

number of moles = mass / molar mass

mass = number of moles x molar mass

= 1.7 x 10^17/6.022 x 10^23.

5 0
2 years ago
Read 2 more answers
If a sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams, what is the half-life of the isotope
qaws [65]

Answer:

<u><em>I HOPE IT WILL BE YOUR ANSWER:</em></u>

Explanation:

As given

60 min = 50 gm        (1)

then we know half-life mean half amount decay time

so we can write as the half of 200 is 100 gm hence

T 1/2 = 100               (2)

solving these two equation by cross multiplication we will get

T 1/2 = 120 min

<em><u>THANKS FOR ASKING QUESTION</u></em>

6 0
3 years ago
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