Answer:
I hope 2 amperes of current passes
A system is contained by its boundary; therefore, the size of a system is limited by its boundary.
Answer:
the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Explanation:
Given the data in the question;
To determine the maximum intensity of an electromagnetic wave, we use the formula;
=
ε₀cE
²
where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )
c is the speed of light ( 3 × 10⁸ m/s )
E
is the maximum magnitude of the electric field
first we calculate the maximum magnitude of the electric field ( E
)
E
= 350/f kV/m
given that frequency of 60 Hz, we substitute
E
= 350/60 kV/m
E
= 5.83333 kV/m
E
= 5.83333 kV/m × (
)
E
= 5833.33 N/C
so we substitute all our values into the formula for intensity of an electromagnetic wave;
=
ε₀cE
²
=
× ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²
= 45 × 10³ W/m²
= 45 × 10³ W/m² × (
)
= 45 kW/m²
Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
The mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.
HOW TO CALCULATE MASS:
- The mass of an object can be calculated by dividing the force applied to the object by its acceleration.
- According to this question, a bus can accelerate from rest to 15.5 m/s over 8.25s. The acceleration can be calculated as follows:
- The mass of the bus = 7500N ÷ 1.88m/s²
- The mass of the bus = 3989.4kg
- Therefore, the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.
Learn more about mass at: brainly.com/question/20259048?referrer=searchResults
Answer:
1752.14 tonnes per year.
Explanation:
To solve this exercise it is necessary to apply the concepts related to power consumption and power production.
By conservation of energy we know that:

Where,
Production of Power
Consumption of power
Where the production of power would be,

Where,
m = Total mass required
Energy per Kilogram
Efficiency
The problem gives us the aforementioned values under a production efficiency of 45%, that is,


Replacing the values we have,

Solving for m,


We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,

tonnes per year.