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forsale [732]
3 years ago
14

What are the elements needed for effective teamwork?

Physics
2 answers:
melamori03 [73]3 years ago
7 0
Communication, tolerance, patience
Elza [17]3 years ago
7 0

Answer:

The five elements of successful teamwork

-Communication: Effective communication is the most important part of teamwork and involves consistently updating each person and never assuming that everyone has the same information. ...

-Delegation: Teams that work well together understand the strengths and weaknesses of each team member. ...

-Efficiency: ...

-Ideas: ...

-Support:

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What is the current if 4C of charge passes in 2 s?
julia-pushkina [17]

Answer:

I hope 2 amperes of current passes

8 0
3 years ago
What is true of systems in terms of their size and boundaries?
Nataly [62]
A system is contained by its boundary; therefore, the size of a system is limited by its boundary.
5 0
4 years ago
Read 2 more answers
In the United States, household electric power is provided at a frequency of 60 HzHz, so electromagnetic radiation at that frequ
grigory [225]

Answer:

the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Explanation:

Given the data in the question;

To determine the maximum intensity of an electromagnetic wave, we use the formula;

I = \frac{1}{2}ε₀cE_{max²

where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )

c is the speed of light ( 3 × 10⁸ m/s )

E_{max is the maximum magnitude of the electric field

first we calculate the maximum magnitude of the electric field ( E_{max  )

E_{max = 350/f kV/m

given that frequency of 60 Hz, we substitute

E_{max = 350/60 kV/m

E_{max = 5.83333 kV/m

E_{max = 5.83333 kV/m × ( \frac{1000 V/m}{1 kV/m} )

E_{max = 5833.33 N/C

so we substitute all our values into the formula for  intensity of an electromagnetic wave;

I = \frac{1}{2}ε₀cE_{max²

I = \frac{1}{2} × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²

I = 45 × 10³ W/m²

I = 45 × 10³ W/m² × ( \frac{1 kW/m^2}{10^3W/m^2} )

I = 45 kW/m²

Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

7 0
3 years ago
What is the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25
alexandr1967 [171]

The mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

HOW TO CALCULATE MASS:

  • The mass of an object can be calculated by dividing the force applied to the object by its acceleration.

  • According to this question, a bus can accelerate from rest to 15.5 m/s over 8.25s. The acceleration can be calculated as follows:

  • a = (v - u)/t

  • a = 15.5 - 0/8.25

  • a = 15.5/8.25

  • a = 1.88m/s²

  • The mass of the bus = 7500N ÷ 1.88m/s²

  • The mass of the bus = 3989.4kg

  • Therefore, the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

Learn more about mass at: brainly.com/question/20259048?referrer=searchResults

3 0
3 years ago
Assume that in 2010 the United States will need 2.0×1012 watts of electric power produced by thousands of 1000 MW power plants.
Alex73 [517]

Answer:

1752.14 tonnes per year.

Explanation:

To solve this exercise it is necessary to apply the concepts related to power consumption and power production.

By conservation of energy we know that:

\dot{P} = \bar{P}

Where,

\dot{P} = Production of Power

\bar{P} = Consumption of power

Where the production of power would be,

\dot{P} = m \dot{E}\eta

Where,

m = Total mass required

\dot{E} = Energy per Kilogram

\eta =Efficiency

The problem gives us the aforementioned values under a production efficiency of 45%, that is,

\dot{P} = \bar{P}

m \dot{E}\eta = \bar{P}

Replacing the values we have,

m(8*10^13)(0.45) = 2*10^{12}

Solving for m,

m = \frac{ 2*10^{12}}{(8*10^13)(0.45)}

m = 0.0556 \frac{kg}{s}

We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,

m = 0.556\frac{kg}{s}*(\frac{3.1536*10^7s}{1year})(\frac{1ton}{1000kg})

m = 1752.14tonnes per year.

8 0
3 years ago
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