A car with mass 1600 kg drives around a flat circular track of radius 28.0 m. The coefficient of friction between the car tires

Question

3 years ago

5

and the track is 0.830. The car is traveling at the maximum speed possible without losing traction.

1 answer:

egoroff_w [7] · Answer 1 · 2022-06-19T09:05:58+03:00

Answer:

v=15.24 m/s

Explanation:

Given that

Mass ,m= 1600 kg

radius ,r= 28 m

Coefficient of friction ,μ = 0.83

The radial force on the car when it takes turn

$F=\dfrac{mv^2}{r}$

The friction force on the car

Fr= μ m g

The condition for motion without losing traction

F= Fr

$\dfrac{mv^2}{r}=\mu\ m g$

v²=μ r g

$v=\sqrt{\mu\ r g}$

Now by putting the values

$v=\sqrt{0.83\times 28\times 10}\ m/s$ ( take g=10m/s²)

v=15.24 m/s

The speed of the car will be 15.24 m/s