The ammeter reading (current) will decrease.
V=IR
I = V/R
so I is inversely proportional to R, i.e. increasing R will cause I to decrease
Answer:
the answer is d
Explanation:
the more mass there is, the larger the gravitational pull is.
I am positive with my and answer and i think yes
Explanation:
For the reaction.......
H
2
O
(
l
)
+
Δ
→
H
2
O
(
g
)
WHERE BOTH PRODUCT AND REACTANT ARE AT
100
∘
C
,
..........
Δ
H
∘
vaporization
=
40.66
⋅
k
J
⋅
m
o
l
−
1
And thus we need to assess the molar quantity of the water vaporized......
Δ
H
rxn
=
5.00
⋅
g
18.01
⋅
g
⋅
m
o
l
−
1
×
40.66
⋅
k
J
⋅
m
o
l
−
1
=11.3 kJ
