Explanation:
The given data is as follows.
mass (m) = 0.160 kg, spring constant (k) = 8 n/m,
Maximum speed (
) = 0.350 m/s
Formula for angular frequency is as follows.


= 7.07 rad/sec
(a) Formula to calculate the amplitude is as follows.

A = 
= 
= 0.05 m
Hence, value of amplitude is 0.05 m.
(b) Displacement = 0.030 m
Formula for mechanical energy is as follows.
M.E = 
Putting the values into the above formula as follows.
M.E = 
= 
=
Joule
For x = 0.03,
As, P.E = 
= 
= 
Hence, calculate the kinetic energy as follows.
K.E = M.E - P.E
= (
-
) J
=
J
Thus, we can conclude that kinetic energy of the puck when the displacement of the glider is 0.0300 m is
J.
Answer:
Change in Potential energy, pe = Final potential energy - Initial potential energy
Explanation:
∆p.e = Final p.e - Initial p.e
From the equation ∆p.e = (mgh) final - (mgh) initial
Answer:
D. The oxygen side is partially negative because electrons are pulled toward the oxygen side.
Explanation:
The water molecule is polar by the virtue of covalent bonds and the hydrogen bonds within and between its molecule.
The oxygen side is partially negative because the electrons are pulled toward the oxygen side.
Between oxygen and hydrogen that makes up the water molecule, oxygen is more electronegative.
An electronegative atom has more affinity for electrons. Since the electrons in the molecule of water is shared between hydrogen and oxygen, the more electronegative specie which is water draws the electron more to itself.
This leaves a net negative charge on the oxygen atom.
A front is defined as a "boundary" that separates two masses of different air densities. I am not entirely sure, but I think the answers are either C or D, but I'm mostly convinced it's option D.
Answer : The volume of water in the pool is, 2473 ft³
Explanation :
First we have to calculate the average depth.
Given:
Diameter = 30 ft
Depth range : 1 to 6 ft linearly
average depth =
Now we have to calculate the volume of water in the pool.
Volume = area × average depth
V = π × (radius)² × 3.5
V = π × (30/2)² × 3.5
V = π × (15)² × 3.5
V = π × 225 × 3.5
V = 3.14 × 225 × 3.5
V = 2472.75 ft³ ≈ 2473 ft³
Therefore, the volume of water in the pool is, 2473 ft³