What is 39.4x1.7<br> pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

20 points! <br><br> Which statement is not used to prove that ΔFGH is similar to ΔFIJ?

Juliette [100K]

Answer:

Point F, J and H are collinear

3 0

3 years ago

What is the 32nd term of the arithmetic sequence where a1 = –33 and a9 = –121?

Aleksandr-060686 [28]

$a_1=-33;\ a_9=-121\\\\a_9-a_1=8d\\\\8d=-121-(-33)\\8d=-121+33\\8d=-88\ \ \ \ |divide\ both\ sides\ by\ 8\\d=-11\\\\a_{32}=a_1+31d\\\\a_{32}=-33+31\cdot(-11)=-33-341=-374\\\\Answer:\boxed{a_{32}=-374}$

8 0

3 years ago

Read 2 more answers

Sarah is playing a game in which she rolls a number cube 20 times. The results are recorded in the chart below. What is the expe

elena55 [62]

Sarah rolled a one 3 times and rolled a three 1 time in a total of 20 rolls. She rolled one or three 4 times out of 20. Therefore,

$\frac{4}{20} = 0.2$

The answer is A.

4 0

4 years ago

mariarad [96]

Answer:

$p_v =P(z>2.087) =0.0184$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the mean for the control group it's not significantly higher than the mean of the treatment group by 1 point.

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

$\sigma=2.5$

And the statistic is given by this formula:

$z=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sigma\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}$

Where z follows a normal standard distribution

The system of hypothesis on this case are:

Null hypothesis: $\mu_c \leq \mu_t+1$

Alternative hypothesis: $\mu_c >\mu_t+1$

Or equivalently:

Null hypothesis: $\mu_c - \mu_t \leq 1$

Alternative hypothesis: $\mu_c-\mu_t>1$

Our notation on this case :

$n_c =45$ represent the sample size for group control

$n_t =45$ represent the sample size for group treatment

$\bar X_c =5.2$ represent the sample mean for the group control

$\bar X_t =3.1$ represent the sample mean for the group treatment

And now we can calculate the statistic:

$z=\frac{(5.2-3.1)-(1)}{2.5\sqrt{\frac{1}{45}}+\frac{1}{45}}=2.087$

And now we can calculate the p value using the alternative hypothesis:

$p_v =P(z>2.087) =0.0184$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the mean for the control group it's not significantly higher than the mean of the treatment group by 1 point.

5 0

3 years ago

Patricia needs 2 pints of purple icing to decorate cupcakes. She will use the following recipe for 1 pint of purple icing.

Lerok [7]

Answer:

double

Step-by-step explanation:

double the teaspoons so you can get the amount you need for 2 pints

double the amount and then divided it

4 0

3 years ago

What is 39.4x1.7 pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee