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Mnenie [13.5K]
3 years ago
7

2. For the following reaction, calculate how many moles of each product are formed when 0.356

Chemistry
1 answer:
Marysya12 [62]3 years ago
8 0

Answer:

\large \boxed{\text{0.356 mol each of PbO and SO}_{2}}}  

Explanation:

            2PbS + 3O₂ ⟶ 2PbO + 2SO₂

n/mol:  0.356  

1. Moles of PbO

2 mol of PbO are formed from 2 mol of PbS

\text{Moles of PbO} = \text{0.356 mol PbS} \times \dfrac{\text{2 mol PbO}}{\text{2 mol PbS}} = \textbf{0.356 mol PbO}

2. Moles of SO₂

2 mol of SO₂ are formed from 2 mol of PbS

\text{Moles of SO}_{2} = \text{0.356 mol PbS} \times \dfrac{\text{2 mol SO}_{2}}{\text{2 mol PbS}} = \textbf{0.356 mol SO}_{2}\\\\\text{The reaction produces } \large\boxed{\textbf{0.356 mol of PbO and 0.356 mol of SO}_{2}}

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