Question

2. For the following reaction, calculate how many moles of each product are formed when 0.356

Answer 1

Answer:

$\large \boxed{\text{0.356 mol each of PbO and SO}_{2}}}$  

Explanation:

            2PbS + 3O₂ ⟶ 2PbO + 2SO₂

n/mol:  0.356  

1. Moles of PbO

2 mol of PbO are formed from 2 mol of PbS

$\text{Moles of PbO} = \text{0.356 mol PbS} \times \dfrac{\text{2 mol PbO}}{\text{2 mol PbS}} = \textbf{0.356 mol PbO}$

2. Moles of SO₂

2 mol of SO₂ are formed from 2 mol of PbS

$\text{Moles of SO}_{2} = \text{0.356 mol PbS} \times \dfrac{\text{2 mol SO}_{2}}{\text{2 mol PbS}} = \textbf{0.356 mol SO}_{2}\\\\\text{The reaction produces } \large\boxed{\textbf{0.356 mol of PbO and 0.356 mol of SO}_{2}}$