Answer:
Sulfur reacts with oxygen to form sulfur dioxide. When nonmetals reactwith one another, the product is a molecular compound. Often, the nonmetal reactants can combine in different ratios and produce different products. Sulfur can also combine with oxygen to produce sulfur trioxide.
Answer:
31.3 g
The answer is higher than the true answer.
Explanation:
By neglecting the heat lost by other processes, the energy conservation states that:
Qcooling + Qevaporate = 0
The cooling process happens without phase change, so the heat can be calculated by:
Qcooling = m*c*ΔT
Where m is the mass, c is the heat capacity (cwater = 4184 J/kg.K), and ΔT is the temperature variation (final - initial).
The evaporate process happen without changing of temperature (pure substance), and the heat can be calculated by:
Qevaporate = m*L
Where m is the mass evaporated and L is the heat of evaporation (2340000 J/kg).
0.350*4184*(45 - 95) + m*2340000 = 0
2340000m = 73220
m = 0.0313 kg
m = 31.3 g
Because of the assumptions made, the real mass is not that was calculated. There'll be changing mass when the coffee is cooling, and there'll be heat loses by other processes because the system is not isolated. Also, the substance is not pure. So, there'll be more factors at the energy equation, thus, the answer is higher than the true answer.
There are four quantum numbers that describe the placement of electrons in an atom's electron cloud: principal quantum number (n), angular quantum number (l), magnetic quantum number (ml) and electron spin number (ms). When presented, they are written as (n, l, ml, ms).
From the given set, they have same n and l quantum numbers. The n represents the shell, the l as subshell, ml is the orientation in space and ms is the direction of the spin. Therefore, these two electrons of the atom share a subshell but differ in the shape of the orbital only.
The Ka of HClO is 4.0 x 10^-8 at 25 C. The dissociation of HClO is:
HClO + H2O ---> H+ + ClO - T = 25 C
Ka = 4.0 x 10^-8 = [H+][ClO-]/[HClO]
pH = -log[4.0 x 10^-8]
pH = 7.40
pOH = 14 - 7.40
= 6.60
Kb = 10^-6.6