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Match each state of matter with the statement that best describes it.

Stells [14]

Answer:

State of matter is defined as a form in which matter can exist. There are four states of matter known till date. They are as follows:

Solid: Matter is said to be in solid state if it has definite shape and volume. The components of matter are closely packed and have fixed positions within the matter.

Liquid: In liquid state, matter has fixed volume but shape is not fixed, it takes the shape of container in which it is placed. The particles of liquid are close but can move freely or do not have fixed positions.

Gas: Matter in gaseous state has variable volume and shape. The particles of gas are very far from each other thus, they are in constant motion without any fixed position..

Plasma: This state of matter has variable shape and volume. It has neutral atoms, the number of ions and electrons are significant and can move freely in the matter. In order to make plasma, energy is required to strip electron from atom.

According to above definitions, the state of matter is matched with the given statements as follows:

Plasma-Particles are so hot that electrons are stripped from atoms.

Gas-It expands to fill the volume of the container.

Liquid-Particles move past each other freely but do not go fat apart.

Solid-It retains its shape regardless of the shape of the container.

Explanation:

I choose this because It understands how each plasma work.

7 0

3 years ago

Read 2 more answers

The concentration of ag+ in a solution saturated with ag2c2o4(s) is 1.7 × 10-4 m. calculate ksp for ag2c2o4.

Gelneren [198K]

Silver oxalate dissociation equation is following:

Ag₂C₂O₄(s) ⇄ 2Ag⁺(aq) + C₂O₄²⁻(aq)

According to reaction follows next stoichiometric ratio:

[Ag⁺] : [C₂O₄²⁻] = 2 : 1

[C₂O₄²⁻] = [Ag⁺] / 2

[C₂O₄²⁻] = (1.7×10⁻⁴)/2 = 8.5×10⁻⁵ M

So, solubility product constants for silver oxalate is:

Ksp = [Ag⁺]² x [C₂O₄²⁻]

Ksp = [1.7×10⁻⁴]² x [8.5×10⁻⁵]

Ksp = 2.46×10⁻¹²

4 0

3 years ago

Is a situation in which a dominant allele completely masks a recessive allele for a gene.

Bond [772]

Complete dominance.... Hope this helps

4 0

3 years ago

1. Calculate the molarity when 403 g MgSO4 is dissolved to make a 5.25 L solution. Round to two significant digits.

lisov135 [29]

Answer:

1. Molarity of MgSO₄ = 0.6 M

2. Molarity of AgNO₃ = 0.06 M

3. volume of acetic acid = 250 mL

4. Molarity of NaCl= 2.3 M

5. Mass of C₁₂H₂₂O₁₁ = 4.1 g

6. Mass of C₁₀H₈ (naphthalene) = 77 g

7. mass of ethanol = 11 g

8. Mass of DDT = 0.011 mg

Explanation:

Ans 1.

Data given

mass of MgSO₄ = 403

Volume of solution = 5.25 L

Solution:

First we will find mole of solute

no. of moles = mass in grams / Molar mass . . . . . .(1)

Molar mass of MgSO₄ = 24 + 32 + 4(16)

Molar mass of MgSO₄ = 120 g/mol

Put values in equation 1

no. of moles = 403 g / 120 g/mol

no. of moles = 3.36 mol

Now to find molarity

Formula used

Molarity = No. of moles of solute / solution in L . . . . . . (2)

Put Values in above equation

M = 3.36 mol / 5.25 L

M = 0.64

So, round the figure to two significant digits.

Molarity of MgSO₄ = 0.64 M

_____________________

Ans 2.

Data given

mass of AgNO₃ = 1.24 g

Volume of solution = 125 mL

convert mL to L

1000 mL = 1 L

125 mL = 125/1000 = 0.125

Solution:

First we will find mole of solute

no. of moles = mass in grams / Molar mass . . . . . .(1)

Molar mass of AgNO₃ = 108 + 14 + 3(16)

Molar mass of AgNO₃ = 170 g/mol

Put values in equation 1

no. of moles = 1.24 g / 170 g/mol

no. of moles = 0.0073 mol

Now to find molarity

Formula used

Molarity = No. of moles of solute / solution in L . . . . . . (2)

Put Values in above equation

M = 0.0073 mol / 0.125 L

M = 0.06

So, round the figure to two significant digits.

Molarity of AgNO₃ = 0.06 M

______________________

Ans 3.

Data Given:

volume of acetic acid = 500 mL

% solution of acetic acid (M)= 50%

volume of acetic acid needed = ?

Solution:

formula used

percent of solution = volume of solute/ volume of solution x 100

Put Values in above formula

50 % = volume of solute / 500 mL x 100

Rearrange the above equation

volume of solute = 50 x 500 mL /100

volume of solute = 250 mL

So, volume of acetic acid = 250 mL

______________________

Ans 4

Data Given:

Molarity of NaCl (M1) = 6 M

Volume of NaCl (V1) = 750 mL

convert mL to L

1000 ml = 1 L

750 ml = 750/1000 = 0.75 L

Volume of dilute solution (V2)= 2 L

Molarity of dilute solution (M2) = ?

Solution:

Dilution Formula will be used

M1V1 = M2V2 . . . . . . (1)

Put values in equation 1

6 M x 0.75 L = M2 x 2 L

Rearrange the above equation

M2 = 6 M x 0.75 L / 2 L

M2 = 2.25 M

So, round the figure to two significant digits.

Molarity of NaCl= 2.3 M

_________________________

Ans 5.

Data Given:

Molarity of C₁₂H₂₂O₁₁ = 0.16 M

Mass of C₁₂H₂₂O₁₁ (m) = ?

Volume of dilute solution = 75 mL

convert mL to L

1000 ml = 1 L

75 ml = 75/1000 = 0.075 L

Solution:

As we know

Molarity = no.of moles/ liter of solution . . . . . . .(1)

we also know that

no.of moles = mass in grams / molar mass . . . . . (2)

Combine both equation 1 and 2

Molarity = (mass in grams / molar mass) / liter of solution . . . . (3)

Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 12(12) +22(1) +11(16)

Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 144 +22 + 176

Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 342 g/mol

Put values in equation in equation 3

0.16 M = (mass in grams / 342 g/mol) / 0.075 L

Rearrange the above equation

mass in grams = 0.16 mol/L x 0.075 L x 342 g/mol

mass in grams = 4.104 g

So, round the figure to two significant digits.

Mass of C₁₂H₂₂O₁₁ = 4.1 g

____________________

The remaing portion is in attachment

8 0

4 years ago

What is the Net Force? 2N > 4N - SN

maria [59]

The net force is SN haha

5 0

4 years ago