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3 years ago

How are sponges and he coral in coral reefs similar

Chemistry

1 answer:

r-ruslan [8.4K]3 years ago

8 0

Answer:

They are both alive organisms. They can breathe and they are known as living creatures. The stay in the same place and food comes to them and they dont hunt for food. They are both like traps.

Explanation:

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Does a periodic table indicate the occurrence of elements

guajiro [1.7K]

Answer:

Explanation:

it only shows the atomic number and basically the chemical behavior of the element

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2 years ago

This is a material that allows heat/electricity to transfer.

Anvisha [2.4K]

A material that allows heat/electricity to transfer is called a conductor.

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3 years ago

Read 2 more answers

The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.160 M NaOH. It requires 18.

olchik [2.2K]

Answer:

Approximately $0.291\; \rm M$ (rounded to two significant figures.)

Explanation:

The unit of concentration $\rm M$ is the same as $\rm mol \cdot L^{-1}$ (moles per liter.) On the other hand, the volume of both the $\rm NaOH$ solution and the original $\rm HCl$ solution here are in milliliters. Convert these two volumes to liters:

$V(\mathrm{NaOH}) = 18.2\; \rm mL = 18.2 \times 10^{-3}\; \rm L = 0.0182\; \rm L$ .
$V(\text{$\mathrm{HCl}$, original}) = 10.0\; \rm mL = 10.0\times 10^{-3}\; \rm L = 0.0100\; \rm L$ .

Calculate the number of moles of $\rm NaOH$ in that $0.0182\; \rm L$ of $0.160\; \rm M$ solution:

$\begin{aligned} n(\mathrm{NaOH}) &= c(\mathrm{NaOH})\cdot V(\mathrm{NaOH})\\ &= 0.160\; \rm mol \cdot L^{-1} \times 0.0182\; \rm L \approx 0.00291\; \rm mol\end{aligned}$ .

$\rm HCl$ reacts with $\rm NaOH$ at a one-to-one ratio:

$\rm HCl\; (aq) + NaOH\; (aq) \to NaCl\; (aq) + H_2O\; (l)$ .

Coefficient ratio:

$\displaystyle \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} = 1$ .

In other words, one mole of $\rm NaOH$ would neutralize exactly one mole of $\rm HCl$ . In this titration, $0.291\; \rm mol$ of $\rm NaOH\!$ was required. Therefore, the same amount of $\rm HC$ should be present in the original solution:

$\begin{aligned}&n(\text{$\mathrm{HCl}$, original})\\ &= n(\mathrm{NaOH})\cdot \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} \\ &\approx 0.00291\; \rm mol \times 1 = 0.00291\; \rm mol\end{aligned}$ .

Calculate the concentration of the original $\rm HCl$ solution:

$\displaystyle c(\text{$\mathrm{HCl}$, original}) = \frac{n(\text{$\mathrm{HCl}$, original})}{V(\text{$\mathrm{HCl}$, original})} \approx \frac{0.00291\; \rm mol}{0.0100\; \rm L} \approx 0.291\; \rm M$ .

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3 years ago

The correct mathematical expression for finding the molar solubility (s) of sn(oh)2 is:

lara [203]

Answer is: Ksp = 4s³.
Balanced chemical reaction (dissociation) of strontium hydroxide:
Sr(OH)₂(s) → Sr²⁺(aq) + 2OH⁻(aq).
Ksp(Sr(OH)₂) = [Sr²⁺]·[OH⁻]².
[Sr²⁺] = s.
[OH⁻] = [Sr²⁺] = 2s
Ksp = (2s)² · x = 4s³.
Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.
[Sr²⁺] is equilibrium concentration of iumcations.
[OH⁻] is equilibrium concentration of hydroxide anions.

7 0

3 years ago

How many moles of glucose (C6H12O6) are in 5.0 liters of a 2.5 M C6H12O6 solution?

zhannawk [14.2K]

N = M x V

n = 2.5 x 5.0

n = 12.5 moles of C6H12O6

5 0

2 years ago