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mixas84 [53]
3 years ago
8

How are sponges and he coral in coral reefs similar

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer:

They are both alive organisms. They can breathe and they are known as living creatures. The stay in the same place and food comes to them and they dont hunt for food. They are both like traps.

Explanation:

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You have lost nearly 6 inches of top soil on your 200 acre field in the last 10 years. The problem seems to be getting even wors
qaws [65]
You could consider building an irrigation system.
6 0
3 years ago
How many grams of H3PO4 are in 234 mL of a 2.5 M solution of H3PO4?
motikmotik

Answer:

57 grams of H3PO4

Explanation:

M= moles/ liters

convert mL to L

234 mL x 1L/1000mL = 0.234L

Rearrange the Molarity formula to solve for moles.

moles= MxL

moles= 2.5M x 0.234L

moles= 0.585 mol

Use the molar mass of H3PO4 to get to grams

0.585 mol x 97.994 grams/1 mol = 57.326 grams of H3PO4

round to two sig figs for 57 grams

5 0
2 years ago
A decomposition reaction has a half life of 578 years. (a) What is the rate constant for this reaction? (b) How many years does
maw [93]

Answer:

0.001199 year^{-1} is the rate constant for this reaction.

It will take 1.73\times 10^3 years to concentration to reach 12.5% of its original value.

Explanation:

A decomposition reaction follows first order kinetics:

Half life of the reaction = t_{1/2}=578 years

Rate constant of the reaction = k

For first order reaction, half life and rate constant are linked with an expression :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{578 years}=0.001199 year^{-1}

0.001199 year^{-1} is the rate constant for this reaction.

Initial concentration of reactant =[A_o] =  x

Final concentration of reactant after time t =[A] =  12.5% of x = 0.125x

The integrated law of first order reaction :

[A]=[A_o]\times e^{-kt}

0.125x=x\times e^{-0.001199 year^{-1}\times t}

t = 1,734.31 years =1.73\times 10^3 years

It will take 1.73\times 10^3 years to concentration to reach 12.5% of its original value.

3 0
3 years ago
How many milliliters of a 0.215 molar solution are required to contain 0.0867 mol of NaBr
JulsSmile [24]

Answer: 403ml

Explanation:

M=\frac{mol}{L}

Solve for L;

L=\frac{mol}{M}\\L=\frac{0.0867mol}{0.215M}\\ L=0.403L

Convert to mililiters

0.403L(\frac{1000ml}{1L})=403ml

3 0
2 years ago
Help me pls I put 49 point( every single point that I have) pls help me
Aliun [14]

Answer:

Chemical reaction, compound, molecule, covalent bonds, ionic bonds, ions. (first page)

Oxygen and hydrogen, 1 hydrogen 2 oxygen, H2O, a covalent bond, then mark off is always a liquid. (Second page)

Explanation:

6 0
3 years ago
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