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Anon25 [30]
3 years ago
11

What is the relationship between the frequency and the speed of the wave?

Physics
1 answer:
GenaCL600 [577]3 years ago
7 0
If everything else stays the same, the speed is proportional to the frequency of the wave. So if everything else is the same, if you double the speed you would double the frequency.
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A maser is a laser-type device that produces electromagnetic waves with frequencies in the microwave and radio-wave bands of the
rusak2 [61]

Answers:

a) T=7.04(10)^{-10} s

b) 5.11(10)^{12} cycles

c) 2.06(10)^{26} cycles

d) 46000 s

Explanation:

<h2>a) Time for one cycle of the radio wave</h2>

We know the maser radiowave has a frequency f of 1,420,405,751.786 cycles/s

In addition we know there is an inverse relation between frequency and time T:

f=\frac{1}{T} (1)

Isolating  T: T=\frac{1}{f} (2)

T=\frac{1}{1,420,405,751.786 cycles/s} (3)

T=7.04(10)^{-10} s (4) This is the time for 1 cycle

<h2>b) Cycles that occur in 1 h</h2>

If 1h=3600s and we already know the amount of cycles per second 1,420,405,751.786 cycles/s, then:

1,420,405,751.786 \frac{cycles}{s}(3600s)=5.11(10)^{12} cycles This is the number of cycles in an hour

<h2>c) How many cycles would have occurred during the age of the earth, which is estimated to be 4.6(10)^{9} years?</h2>

Firstly, we have to convert this from years to seconds:

4.6(10)^{9} years \frac{365 days}{1 year} \frac{24 h}{1 day} \frac{3600 s}{1 h}=1.45(10)^{17} s

Now we have to multiply this value for the frequency of the maser radiowave:

1,420,405,751.786 cycles/s (1.45(10)^{17} s)=2.06(10)^{26} cycles This is the number of cycles in the age of the Earth

<h2>d) By how many seconds would a hydrogen maser clock be off after a time interval equal to the age of the earth?</h2>

If we have 1 second out for every 100,000 years, then:

4.6(10)^{9} years \frac{1 s}{100,000 years}=46000 s

This means the maser would be 46000 s off after a time interval equal to the age of the earth

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A convex mirror always forms a real and diminished image. That is, the image formed is erect or right-side up and smaller in size. Therefore, Lin Yao should describe her reflection on the back side of the mirror to be right-side up and smaller.

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