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sineoko [7]
3 years ago
12

PLEASE HELP ASAPPP!!!!!

Mathematics
2 answers:
ddd [48]3 years ago
4 0
Uhhh use so carson in
9966 [12]3 years ago
3 0

Answer: 10 in

Step-by-step explanation:

8 in/32 ft = xin / 40 ft

40(8)/32 = 10 in

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The area of the circle above is 1,519.76 units squared. what is the circumference
murzikaleks [220]
In order to find the circumference, we first need to find the radius.  We have the area, so we can find the radius.  We set up this equation:

1519.76= \pi  r^{2}

We begin by dividing both sides by pi.

483.76 = r^{2}

Next, we take the square root of both sides to get the radius.

r = 22.

Next, we plug this into the formula for the circumference, 2 pi r

C = 2 \pi *22=138.23

So, the circumference of this circle is 138.23 units.
5 0
4 years ago
the temperature of dry ice is -109.5°F this is 184.2°F less than the outside temperature. What is the outside temperature?
AlladinOne [14]

Answer:

<em>74.7°F</em>

Step-by-step explanation:

You need to add 184.2°F to -109.5°F.

184.2°F + (-109.5°F) =

= 184.2°F - 109.5°F

= 74.7°F

4 0
3 years ago
There are 50 bacteria in a test tube. After one hour, the number of bacteria is 100. After two hours, the number of bacteria is
r-ruslan [8.4K]
I think its n(50 x 2)
7 0
3 years ago
Read 2 more answers
Assume that BK Call Center receives 2 phone calls in one hour on average. If the department works 10 hours a day receiving the c
MrMuchimi

Using the Poisson distribution, the probabilities are given as follows:

A. 0.0888 = 8.88%.

B. 0.1354 = 13.54%.

C. 0.8646 = 86.46%.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

Item a:

10 hours, 2 calls per hour, hence the mean is given by:

\mu = 2 \times 10 = 20.

The probability is P(X = 20), hence:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 20) = \frac{e^{-20}20^{20}}{(20)!} = 0.0888

Item b:

1 hour, hence the mean is given by:

\mu = 2

The probability is P(X = 0), hence:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}2^{0}}{(0)!} = 0.1354

Item c:

The probability is:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1354 = 0.8646

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

5 0
2 years ago
The bed of a truck is stacked with with boxes of paper. The boxes are stacked 5 boxes deep by 4 boxes high by 4 boxes across
marysya [2.9K]

Answer:

3

Step-by-step explanation:

The boxes are stacked 5 boxes deep by 4 boxes high by 4 boxes across, then there are 5\cdot 4\cdot 4=80 boxes in total.

The mass of 1 box of paper is 22.5 kilograms, so 80 boxes weigh 22.5\cdot 80=1800 kilograms.

When the driver is in the truck, the mass is 2948.35 kilograms, then the total mass is

2948.35+1800=4748.35\ kg.

Let n be the number of boxes of paper the driver must deliver at the first stop. Their weigth is 22.5n kg and the weight of the truck without n boxes is

4748.35-22.5n\ kg.

Trucks with a mass greater than 4700 kilograms are not allowed over the bridge, thus

4748.35-22.5n48.35,\\ \\n>\dfrac{967}{450}=2\dfrac{67}{450}.

Hence, the driver must deliver at least 3 boxes at the first shop.

8 0
3 years ago
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