A vertical steel beam in a building supports a load of 6.0×10⁴. If the length of the beam is 4.0m and it's cross-sectional area
1 answer:
Answer:
DL = 1.5*10^-4[m]
Explanation:
First we will determine the initial values of the problem, in this way we have:
F = 60000[N]
L = 4 [m]
A = 0.008 [m^2]
DL = distance of the beam compressed along its length [m]
With the following equation we can find DL
Note: The question should be related with the distance, not with the diameter, since the diameter can be found very easily using the equation for a circular area.
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The question is incomplete. The complete question is :
The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.
A 4-column table with 3 rows. The first column labeled Body has entries 1, 2, 3. The second column labeled Mass (grams) has entries 500, 1500, 750. The third column labeled Engine has entries 1, 2, 3. The fourth column labeled Force (Newtons) has entries 25, 20, 30.
Based on Newton’s laws of motion, which combination of rocket bodies and engines will result in the acceleration of 40 m/s2 at the start of the launch?
Body 3 + Engine 1
Body 2 + Engine 2
Body 1 + Engine 2
Body 1 + Engine 1
Solution :
Given :
Body Mass (gram) Engine Force (newtons)
1 500 1 25
2 1500 2 20
3 750 3 30
The body 1 has a mass of 500 gram which is equal to 0.5 kg
And engine 2 has a force of 20 newtons.
We know that according to Newton's laws of motion,
Force = mass x acceleration
20 = 0.5 x acceleration
Acceleration
Therefore, based on laws of motion of Newton, the Body 1 + Engine 2 combination of the rocket bodies and engines will result in an acceleration of at the start of the launch.