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pishuonlain [190]
3 years ago
11

A vertical steel beam in a building supports a load of 6.0×10⁴. If the length of the beam is 4.0m and it's cross-sectional area

is 8.0×10^-3m². Find the diameter of the beam which is compressed along its length
Physics
1 answer:
Furkat [3]3 years ago
3 0

Answer:

DL = 1.5*10^-4[m]

Explanation:

First we will determine the initial values of the problem, in this way we have:

F = 60000[N]

L = 4 [m]

A = 0.008 [m^2]

DL = distance of the beam compressed along its length [m]

With the following equation we can find DL

\frac{F}{A} = Y*\frac{DL}{L} \\where:\\Y = young's modulus = 2*10^{11} [Pa]\\DL=\frac{F*L}{Y*A} \\DL=\frac{60000*4}{2*10^{11} *0.008} \\DL= 1.5*10^{-4} [m]

Note: The question should be related with the distance, not with the diameter, since the diameter can be found very easily using the equation for a circular area.

A=\frac{\pi}{4} *D^{2} \\D = \sqrt{\frac{A*4}{\pi} } \\D =  \sqrt{\frac{0.008*4}{\\pi } \\\\D = 0.1[m]

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A flywheel of J = 50 kg-m2 initially standing still is subjected to a constant torque. If the angular velocity reaches 20 Hz in
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Answer:

\tau = 1256.5\ N.m

Explanation:

given,

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time ,t = 5 s

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ω = 125.66 rad/s

now, angular acceleration calculation

\alpha = \dfrac{\omega_f-\omega_i}{t}

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