The distance traveled by the box over the first 4 s is 16 m.
To solve the problem above, First, we apply newton's Fundamental equation of force.
<h3 /><h3>Newton's fundamental equation of force:</h3>
F = ma...................... Equation 1
Where
- F = Force
- m = mass of the box
- a = acceleration
make "a " the subject of the equation
a = F/m...................... Equation 2
From the question,
Given:
Substitute these values into equation 2
a = 10/5
a = 2 m/s²
Finally, we use the equation of motion to calculate the distance it will travel over the given period of time.
<h3><u>Equation of motion</u></h3>
s = ut+at²/2........................... Equation 3
Where:
- s = total distance traveled
- t = time
- u = initial velocity
Given:
- t = 4 s
- u = 0 m/s (at rest)
Substitute these values into equation 3
- s = 0(4)+(2×4²)/2
- s = 0+32/2
- s = 16 m
Hence, the distance traveled by the box over the first 4 s is 16 m
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Answer:
mass of the meter stick=0.063 kg
or
mass of the meter stick=63.3 g
Explanation:
Given data
m₁=41.0g=0.041kg
r₁=(39.2 - 23)cm
r₂=(49.7 - 39.2)cm
g=9.8 m/s²
To find
m₂(mass of the meter stick)
Solution
The clockwise and counter-clockwise torques must be equal if the meter stick is in rotational equilibrium
The distance covered by the body is 114.3 m
Explanation:
The work done by a force exerted on an object is given by
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
For the object in this problem, we have
F = 350 N is the force applied
is the work done
if we assume that the force is applied parallel to the motion of the object
Solving for d, we find the distance covered by the object:
Learn more about work:
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Answer : The final temperature is, 
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of ice = 
= specific heat of water = 
= mass of ice = 50 g
= mass of water = 200 g
= final temperature = ?
= initial temperature of ice = 
= initial temperature of water = 
Now put all the given values in the above formula, we get:
Therefore, the final temperature is,
Work, Kinetic Energy and Potential Energy
6.1 The Important Stuff 6.1.1 Kinetic Energy
For an object with mass m and speed v, the kinetic energy is defined as K = 1mv2
2
(6.1)
Kinetic energy is a scalar (it has magnitude but no direction); it is always a positive number; and it has SI units of kg · m2/s2. This new combination of the basic SI units is
known as the joule:
As we will see, the joule is also the unit of work W and potential energy U. Other energy
1joule = 1J = 1 kg·m2 (6.2) s2
units often seen are:
6.1.2 Work
1erg=1g·cm2 =10−7J 1eV=1.60×10−19J s2
When an object moves while a force is being exerted on it, then work is being done on the object by the force.
If an object moves through a displacement d while a constant force F is acting on it, the force does an amount of work equal to
W =F·d=Fdcosφ (6.3)
where φ is the angle between d and F.
