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chubhunter [2.5K]
3 years ago
9

The _____ deflects these winds to the right in the northern hemisphere and to the Southern Hemisphere

Physics
1 answer:
almond37 [142]3 years ago
6 0

Answer:

Coriolis Effect

Explanation:

The Coriolis effect is responsible for the deflection of winds to the right in the Northern hemisphere and to the right in the Southern hemisphere. It is an effect that occurs because of the rotation of the earth around its axis.

The implication of this is that in areas of low pressure in the Northern hemisphere, winds tend to blow in anticlockwise direction, and in areas of high pressure, it blows in a clockwise direction. The opposite of this happens in the Southern hemisphere.

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Which sentence from the passage shows that the function of the river depicted here has carried through to modern times?

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A soccer ball is released from rest at the top of a grassy incline. After 6.2 seconds, the ball travels 47 meters. One second la
alexandr1967 [171]

Answer:

(a) a = 2.44 m/s²

(b) s = 63.24 m

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(a)

We will use the second equation of motion here:

s = v_it+\frac{1}{2}at^2

where,

s = distance covered = 47 m

vi = initial speed = 0 m/s

t = time taken = 6.2 s

a = acceleration = ?

Therefore,

47\ m = (0\ m/s)(6.2\ s)+\frac{1}{2}a(6.2\ s)^2\\\\a = \frac{2(47\ m)}{(6.2\ s)^2}

<u>a = 2.44 m/s²</u>

<u></u>

(b)

Now, we will again use the second equation of motion for the complete length of the inclined plane:

s = v_it+\frac{1}{2}at^2

where,

s = distance covered = ?

vi = initial speed = 0 m/s

t = time taken = 7.2 s

a = acceleration = 2.44 m/s²

Therefore,

s = (0\ m/s)(6.2\ s)+\frac{1}{2}(2.44\ m/s^2)(7.2\ s)^2\\\\

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6 0
3 years ago
A 6.7 kg block is released from rest on a frictionless inclined plane making an angle of 25.7° with the horizontal. Calculate th
yulyashka [42]

Answer:

So time taken by block to travel 0.5 m from rest will be 0.4853 sec

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We have given mass of the block m = 6.7 kg

angle of inclination \Theta =25.7^{\circ}

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Initial velocity u = 0 m/sec

Acceleration of the block a=gsin\Theta =9.8\times sin25.7^{\circ}=4.243m/sec^2

From second equation of motion we know that S=ut+\frac{1}{2}at^2

So 0.5=0\times t+\frac{1}{2}\times 4.243\times t^2

t^2=0.2356

t = 0.4853 sec

So time taken by block to travel 0.5 m from rest will be 0.4853 sec

5 0
3 years ago
Can electromagnetic waves travel in a vacuum? <br><br> Yes <br> Or<br> No
Sonja [21]

Answer:

Yes

Explanation:

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