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vovikov84 [41]
3 years ago
6

An apple falls from a tree and 2.5 seconds later hits the ground. How fast is the apple falling when it hits the ground? Neglect

air resistance.
O 2.5
05
O 20
0 25
Physics
1 answer:
denis-greek [22]3 years ago
6 0

Answer:

<h2>9.8 m/s²</h2>

Explanation:

<h2>Since the ball rises for 2.5 s, the time to fall is 2.5 s. The acceleration is 9.8 m/s2 everywhere, even when the velocity is zero at the top of the path. Although the velocity is zero at the top, it is changing at the rate of 9.8 m/s² downward.</h2>
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Figure 1 shows cavity wall insulation being installed in the wall of a house.
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The heating curve of an ice-water mixture that is slowly heated to 125??C contains three sloped and two level portions. What do
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4 years ago
Read 2 more answers
A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material,
Ad libitum [116K]

This question is incomplete, the complete question is;

A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material, which forms a hollow tube, has an inner radius a and an outer radius b, and the insulator provides a resistance R between the conductors. If a second insulator, made of the same material and having the same length, is made with double both the inner radius and the outer radius of the first, what resistance would it provide between the conductors

a) (In2)R

b) 4R

c) R/(In2)

d) 2R

e) R

Answer: Option e) R is the correct answer.

Explanation:

Given that;

Inner radius = a

Outer radius = b

Conical Cylinder

∫dR = ∫(edr/2πrL)

R = e/2πL In e |ᵇₐ

R = e/2πL In(b/a) ------------- let this be equation 1

Taking a look at the second cone

a' = 2a

b' = 2a

R' = e/2πL In(2b/2a)

{L = L'}

R' = e/2πL In(b/a) -------let this be equation 2

now lets compare the two equation

R = e/2πL In(b/a)

R' = e/2πL In(b/a)

so R' = R

Therefore Option e) R is the correct answer.

8 0
3 years ago
A horizontal force of 150 N is used to push a 40.0-kg packing crate a distance of 6.00 m on a rough horizontal surface. If the c
icang [17]

Answer:

a. 900 J

b. 0.383

Explanation:

According to the question, the given data is as follows

Horizontal force = 150 N

Packing crate = 40.0 kg

Distance = 6.00 m

Based on the above information

a. The work done by the 150-N force is

W = F x = \mu N x = \mu\ m\ g\ x

W = 150 \times 6

= 900 J

b. Now the coefficient of kinetic friction between the crate and surface is

\mu = \frac {F}{m\timesg}

= \frac{150}{40\times 9.8}

= .383

We simply applied the above formulas so that each one part could calculate

3 0
4 years ago
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