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vlada-n [284]
3 years ago
15

How many grams are of aluminum nitrate are contained in 0.150 moles of Al(NO3)3? ​

Chemistry
1 answer:
Ket [755]3 years ago
6 0

Answer:

31.95 g

Explanation:

find the molar mass of Al(NO3)3

(Al = 27, N = 14, O = 16)

molar mass of Al(NO3)3 = 27+ (14+16×3)×3

= 213 gmol^-

mass = 213 ×0.15

= 31.95g

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