It take more energy to break the bonds of the reactants and less energy is given off when the product bonds are formed.
<h3>What is Energy?</h3>
Energy is defined as the ability to do work. Work is done in the breaking or formation of bonds.
The standard Enthalpy (ΔH) of water which was formed in the given reaction is negative.
ΔH= Δproduct - Δreactant
This means that the energy to break the bonds of the reactants is more.
Read more about Enthalpy here brainly.com/question/14291557
Answer:
I think its A let me know if im wrong
Explanation:
Should be 27300 milligrams
Answer: The standard enthalpy change is -607kJ
Explanation:
The given balanced chemical reaction is,
First we have to calculate the enthalpy of reaction 
.
![\Delta H^o=[n_{C_6H_6}\times \Delta H_f^0_{(C_6H_6)}]-[n_{C_2H_2\times \Delta H_f^0_{(C_2H_2)}]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo%3D%5Bn_%7BC_6H_6%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28C_6H_6%29%7D%5D-%5Bn_%7BC_2H_2%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28C_2H_2%29%7D%5D)
where,
We are given:
Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(1\times 83)]-[(3\times 230)]=-607kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%2083%29%5D-%5B%283%5Ctimes%20230%29%5D%3D-607kJ)
The standard enthalpy change is -607kJ
