All categories

2 years ago

What is the frequency of a photon with an energy of 3.26 x 10-19 J?

Chemistry

1 answer:

Kobotan [32]2 years ago

8 0

Answer:

$from \: eisteins \: energy \: relation : \\ E = hf \\ h \: is \: plancks \: constant\\ 3.26 \times {10}^{ - 19} = 6.63 \times {10}^{ - 34 } \times f \\ f = \frac{3.26 \times {10}^{ - 19} }{6.63 \times {10}^{ - 34} } \\ f = 4.92 \times {10}^{14} \: Hz$

You might be interested in

Why is it important for someone to hold enzymes in their functional shapes

kumpel [21]

Answer:

there are spaces within the enzymes that is active. That active site allows substrates to join in. This helps the enzyme carry out the chemical reaction with the substrate.

Explanation:

4 0

3 years ago

Imagine the reaction A + B ⇌ C + D is at equilibrium, where the forward and reverse reactions are at equal rates. What would hap

kondaur [170]

Answer:

Rate of forward reaction will increase.

Explanation:

Effect of change in reaction condition on equilibrium is explained by Le Chatelier's principle. According to this principle,

If an equilibrium condition of a dynamic reversible reaction is disturbed by changing concentration, temperature, pressure, volume, etc, then reaction will move will in a direction which counteract the change.

In the given reaction,

A + B ⇌ C + D

If concentration of A is increase, then reaction will move in a direction which decreases the concentration of A to reestablish the equilibrium.

As concentration A decreases in forward direction, therefore, rate of forward reaction will increase.

3 0

3 years ago

A covalent bond between an oxygen atom and a hydrogen atom is best described as _____.

Igoryamba

The answer is most likely nonmetals. :)

7 0

3 years ago

How many grams hydrogen in 4.5 mol H2SO4

swat32

H2SO4 ---> 2H^+ + SO4^2-

Hence n H+ = 9 mols

Mass of H = nM = (9*1) = 9g

Alternately

mass of H2SO4= nM= 4.5*98= 441

Mass of H= mass h2so4 * molar mass of H/molar mass of h2so4
Mass of H= 441 * 2/98 = 9g

4 0

3 years ago

Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o

jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

Step 1: The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

Step 2: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

Step 3: Calculate moles of glucose

Moles glucose = Mass glucose / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

Step 4: Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

Step 5: Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

Step 6: Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0

3 years ago