Given the reaction 2Pb(s)+O2(g)= 2PbO(s) and a reactant amount of 451.4 grams, we are asked for the yield of the reaction. The amount of lead present produces 451.4/207.2 *( 2/2) *(223.2) via 100% conversion, 486.26 grams lead (II) oxide. hence the percent yield is 356.7g /<span>486.26 g or equal to 73.35 percent</span>
Answer:
The answer to your question is letter b) X
Explanation:
Data
W = 5 units
X = 6 units
Chemical reaction
2W + 3X ⇒ 3Y + Z
To determine which reactant is the limiting reactant, we must use proportions:
-Theoretical proportion W / X = 2 / 3 = 0.67
- Experimental proportion W / X = 5 / 6 = 0.83
As the experimental proportion is higher than the theoretical proportion, we conclude that the amount of W is higher in the experiment so the limiting reactant is X.
The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.
Co = 10pd/M
Where;
Co = concentration = ?
p = percent of the hydrogen peroxide = 30%
d = Density of hydrogen peroxide = 1.39 g/ml
M = Molar mass = 34 g/mol
Substituting values;
Co = 10 × 30 × 1.39/34
Co = 12.26 M
The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.
Learn more: brainly.com/question/6111443
Answer:
Ammonia and oxygen without catalyst | NH3 + O2 → N2 + H2O. With supply of heat, ammonia reacts with oxygen and produce nitrogen gas and water as products. Nitrogen of ammonia is oxidized to nitrogen gas from -3 oxidation state to 0 oxidation state.
Explanation:
Cytoplasm contains all the material and organelles within a cell.
