<span>A similar thing occurred with the circles as did with the electroscope. When we initially brought the charged pole close to, the bar pulled in the circle since it was of polarization. At that point, once the bar touched the circle, the pole repulsed the circle. This is on the grounds that once the pole and circle touched, the electrons exchanged thus did the protons, consequently leaving the circle with a positive net charge. The nearer the bar is to the circle the more it repulsed, however, it didn't influence the charge of the circle once the circle was touched by the pole.</span>
Answer: Directly through the phospholipid membrane
Explanation:
The cell membrane consist of a phospholipid bilayers structure. In the interior of the membrane, the phospholipid tail are hydrophobic, which makes the cell membrane to be selectively permeable, it is permeable to non polar molecules and impermeable to polar molecules.
Because Steroids are fat soluble, non polar compounds, they can diffuse directly through the hydrophobic, non polar core of the phospholipid bilayer without the use of carrier proteins.
i believe the answer is success of a policy. if this was correct please mark brainliest and lmk if you have any more questions x
Explanation:
The given data is as follows.
, 
Work produced per kJ of heat extracted from hot reservoir = 0.45 kJ = Efficiency
If the device is Carnot cycle then its efficiency will be maximum and its value will be equal to ![[1 - (\frac{T_{c}}{T_{h}} )]](https://tex.z-dn.net/?f=%5B1%20-%20%28%5Cfrac%7BT_%7Bc%7D%7D%7BT_%7Bh%7D%7D%20%29%5D)
Using this relation we will calculate the efficiency as follows.
Efficiency =
= 
= 0.928
Hence, it means that this type of device is possible and the claim is also believable.
Answer:
the answer is unsaturated
Explanation:
A saturated solution contains more solute per volume of solvent than an unsaturated solution. The solute has dissolved until no more can, leaving undissolved matter in the solution. ... In a supersaturated solution, there is more dissolved solute than in a saturated solution.
