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Bond [772]
3 years ago
14

Hello, I need help. (Again TwT)

Mathematics
2 answers:
Effectus [21]3 years ago
7 0
Yes the answer is 2/3
Mkey [24]3 years ago
7 0
The answer is 2 over 3
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Need your help plz and thank you
emmainna [20.7K]

Answer:

Point D

Step-by-step explanation:

Point D(x,y) x=4, y=4/2=2

5 0
3 years ago
What is the product of 180 and <br><br> 5.7×10^2<br><br> expressed in scientific notation?
DerKrebs [107]

The product of 180 and 5.7 x 10^2 is 1.026 x 10^5 (in scientific notation)

hope this helps!

6 0
3 years ago
HELP HELP HELP HELP HELP ITS URGENT :((((​
Ber [7]

Answer: well if you listened on school you wouldn't need help sooo

Step-by-step explanation: LISTEN IN SCHOOL

8 0
3 years ago
Solve the following system of equations algebraically.
Triss [41]

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

( 12 , 15 )

Equation Form:  x = 12 , y = 15

Step-by-step explanation:

7 0
3 years ago
A study of the annual population of gray squirrels in a Texas state park shows the population, S(t), can be represented by the f
Anastasy [175]

The growth rate of the given function is A) 1

Step-by-step explanation:

Step 1; To calculate the rate we need to see the difference between values at different periods of time. We need to calculate the population at different times.

For t = 1 years, S(t) = 273(1.073)t = 273 × 1.073 × 1 = 292.929,

For t = 2 years, S(t) = 273(1.073)t = 273 × 1.073 × 2 = 585.858,

For t = 2 years, S(t) = 273(1.073)t = 273 × 1.073 × 1 = 878.787.

Step 2; To calculate the growth rate, we divide the difference in the values of the present year and the past year by the value in the past year.

Growth rate between t = 1 and t = 2, Growth rate = S(t=2) - S(t=1) / S(t=1)

                                        = 585.858 - 292.929 / 292.929 = 1.

Growth rate between t = 2 and t = 3, Growth rate = S(t=3) - S(t=2) / S(t=2)

                                        = 878.787 - 585.858 / 585.858 = 1.

So the growth rate is A) 1.

4 0
4 years ago
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