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topjm [15]
3 years ago
5

How many moles are in 54g of sliver​

Chemistry
1 answer:
BabaBlast [244]3 years ago
4 0

Answer:

0.50 mols Ag

Explanation:

Given the data, we have:

mass= 54g

molar mass of Silver (Ag): 107.8 g/mol

We want moles, we can convert grams > moles using the molar mass as a "bridge" between the 2.

54g * \frac{1 mol}{107.8 g}= 0.50 mols Ag

Keeping an eye on the units, we'll see 54g get cancelled out by 107.8 g/mol and we'll be left with moles of Silver.

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the symbol for xenon (xe) would be a part of the noble gas notation for the element antimony. cesium.
trapecia [35]

The symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.

For writing the electronic configuration of any element by using the preceding noble gas configuration, we simply use the symbols of noble gas belongs to the previous period of that particular elements. We can't use the symbol of noble gas of same period from which the element belong.

A is the wrong option because the noble gas in the preceding period to the period from which antimony belongs is krypton.

The actual electronic configuration of antimony is as follow:

[Kr] 4d10 5s2 5p3

B is correct option because the noble gas in the preceding period to the period from which Cesium belongs is Xenon.

The actual electronic configuration of Cesium is as follow:

[Xe] 6s1

Thus, we concluded that the symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.

learn more about Noble gas:

brainly.com/question/2094768

#SPJ4

8 0
2 years ago
What is the percent yield for the reaction of nitrogen and hydrogen to produce ammonia, if the theoretical yield was 12.5 g but
koban [17]

Answer:

81.6%

Explanation:

10.2/12.5= 0.816

0.816=81.6%

4 0
3 years ago
When 70.4 g of benzamide (C7H7NO) are dissolved in 850. g of a certain mystery liquid X, the freezing point of the solution is 2
Arlecino [84]

Answer:

1.62

Explanation:

From the given information:

number of moles of benzamide  =\dfrac{70.4 \ g}{121.14 \ g/mol}

= 0.58 mole

The molality = \dfrac{mass \ of \ solute (i.e. \ benzamide )}{mass \ of \ solvent  }

= \dfrac{0.58 }{0.85 }

= 0.6837

Using the formula:

\mathbf {dT  = l   \times  k_f  \times m}

where;

dT = freezing point = 27

l = Van't Hoff factor = 1

kf = freezing constant of the solvent

∴

2.7 °C = 1 × kf ×  0.6837 m

kf = 2.7 °C/ 0.6837m

kf = 3.949 °C/m

number of moles of NH4Cl = \dfrac{70.4 \ g}{53.491 \  g /mol}

= 1.316 mol

The molality = \dfrac{1.316 \ mol}{0.85 \ kg}

= 1.5484

Thus;

the above kf value is used in determining the  Van't Hoff factor for  NH4Cl

i.e.

9.9 = l × 3.949 × 1.5484 m

l = \dfrac{9.9}{3.949 \times 1.5484 \ m}

l = 1.62

5 0
2 years ago
For which of the following solutions would an increase in pressure result in an increase in solubility of a solute?
kozerog [31]

Answer:

gases, liquids and solids

8 0
3 years ago
Oxygen atoms have six outer electrons<br><br> Write the symbol for an oxide ion.
Shkiper50 [21]

Answer:

O^{2-} is the symbol for an oxide ion

7 0
3 years ago
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