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Keith_Richards [23]
3 years ago
12

A small airplane is sitting at rest on the ground. Its center of gravity is 2.58 mm behind the nose of the airplane, the front w

heel (nose wheel) is 0.800 mm behind the nose, and the main wheels are 3.02 mm behind the nose. What percentage of the airplane's weight is supported by the nose wheel
Physics
1 answer:
padilas [110]3 years ago
6 0

Answer:

The percentage of the weight supported by the front wheel is  A= 19.82 %

Explanation:

B] Let the mass of plane be m, force on backwheels be Nb and nosewheel be Nn

Torque equation about nose wheel,

mg*(2.58-0.8) - Nb *(3.02-0.8) = 0

Nb =  mg*(2.58-0.8)/(3.02-0.8) = 0.8018 mg

Nn = mg - Nb = (1-0.8018) mg = 0.1982mg

Weight percentage supported by front wheel = 19.82% answer

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A resistor is connected in series with a power supply of 23.90 V. The current measure is 0.60 A. What is the resistance (in Ω) o
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The resistance in this circuit is 39.8 ohms.

Explanation:

Any circuit having resistor, battery and ammeter connected in series will obey the ohm's law in basic case. So according to the Ohm's law, the current flowing in the circuit through the ammeter will be equal to the voltage shown in the voltmeter or battery and resistor is the proportionality constant. So with this law

V = IR

So, Resistance R = V/I

As the voltage is given as 23.90 V and the current is given as 0.6 A, then resistance is

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Answer:

V₀y = 0 m/s

t = 2.47 s

V₀ₓ = 61.86 m/s

Vₓ = 61.86 m/s

Explanation:

Since, the ball is hit horizontally, there is no vertical component of velocity at initial point. So, the initial vertical velocity (V₀y) will beL

<u>V₀y = 0 m/s</u>

For the initial vertical velocity of golf ball we consider the vertical motion and apply 2nd equation of motion:

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Therefore,

30 m = (0 m/s)(t) + (0.5)(9.8 m/s²)t²

t² = 30 m/4.9 m/s²

t = √6.122 s²

<u>t = 2.47 s</u>

For initial vertical velocity we analyze the horizontal motion of the ball. We neglect the frictional effects in horizontal motion thus the speed remains uniform. Hence,

V₀ₓ = Xt

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V₀ₓ = Initial vertical Velocity = ?

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Therefore,

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<u>V₀ₓ = 61.86 m/s</u>

<u></u>

Due, to uniform motion in horizontal direction:

Final Vertical Velocity = Vₓ = V₀ₓ

Vₓ = 61.86 m/s

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