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Reil [10]
3 years ago
7

The first artificial satellite to orbit the Earth was Sputnik I, launched October 4, 1957. The mass of Sputnik I was 83.5 kg, an

d its distances from the center of the Earth at apogee and perigee were 7330 km and 6610 km, respectively. Find the difference in gravitational potential energy for Sputnik I as it moved from apogee to perigee.
Physics
1 answer:
9966 [12]3 years ago
4 0

Answer:

-4.941*10^8J.

Explanation:

To solve this exercise it is necessary to take into account the concepts related to gravitational potential energy, as well as the concept of perigee and apogee of a celestial body.

By conservation of energy we know that,

\Delta U = \Delta_{perogee}-\Delta_{Apogee}

Where,

U= \frac{-GmM_e}{r}

Replacing

\Delta U = \frac{-GmM_e}{r_p}- \frac{-GmM_e}{r_a}

\Delta U = GmM_e (\frac{1}{r_A}-\frac{1}{r_p})

Our values are given by,

m = 85.5Kg

M_e = 5.97*10^{24}Kg

r_A = 7330Km

r_p = 6610Km

G = 6.67*10^{-11}Nm^2/Kg^2

Replacing at the equation,

\Delta U = (6.67*10^{-11})(85.5)(5.97*10^{24}) (\frac{1}{7330}-\frac{1}{6610})

\Delta U = -4.941*10^8J

Therefore the Energy necessary for Sputnik I as it moved from apogee to perigee was -4.941*10^8J.

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Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart
Romashka [77]

Answer:

E   = 5291.00 N/C

Explanation:

Expression for capacitance is

C = \frac{\epsilon  A}{d}

where

A is area of square plate

D = DISTANCE BETWEEN THE PLATE

C = \frac{\epsilon\times(19\times 10^{-2})^2}{1.5\times 10^{-3}}

C = 24.06 \epsilon

C = 24.06\times 8.854\times 10^{-12} F

C =2.1\times 10^{-10} F

We know that capacitrnce and charge is related as

V = \frac{Q}{C}

 = \frac{2\tiimes 10^{-9}}{2.\times 10^{-10}}

v = 9.523 V

Electric field is given as

E = \frac{V}{d}

   = \frac{9.52}{1.8*10^{-3}}

E   = 5291.00 V/m

E   = 5291.00 N/C

5 0
3 years ago
edward travels 150 kilometers due west and then 200 kilometers in a direction 60 degrees north of west.what is his displacement
laila [671]

The displacement of Edward in the westerly direction is determined as 180.27 km.

<h3>Displacement of Edward</h3>

The displacement of Edward is calculated as follows;

R² = a² + b² - 2abcosθ

R² = 150² + 200² - 2(150 x 200) x cos60

R² = 32500

R = 180.27 km

Thus, the displacement of Edward in the westerly direction is determined as 180.27 km.

Learn more about displacement here: brainly.com/question/321442

#SPJ1

3 0
3 years ago
Which of the following is not a natural resource of light
marta [7]

Answer: Oil lamps are NOT a natural resource of light.

Explanation: Oil lamps have to be lit and do not give off light themselves. You have to make them and light them for them to give light.

8 0
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Jet001 [13]

D) Less than 20.

Explanation:

Equivalent resistance in a parallel combination is less than their individual value.

5 0
3 years ago
It is important to organize your data because
serg [7]
I would say B. hope it helps 
5 0
3 years ago
Read 2 more answers
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