Answer:
2570987.31 m³
Explanation:
Base area = 13 acres = b
Converting to ft²
1 acre = 43,560 ft²
⇒13 acre = 566280 ft²
Height of pyramid = 481 ft = h
Volume
Converting to cubic meters
1 ft = 0.3048 m
⇒1 ft³ = 0.3048×0.3048×0.3048 m³
⇒1 ft³ = 0.3048³ m³
90793560 ft³ = 90793560×0.3048³
⇒90793560 ft³ = 2570987.31 m³
∴ Volume of this pyramid is 2570987.31 m³
Here we apply conservation of linear momentum. The momentum of the truck with cargo and without cargo remains constant. That is,
.
Here are initial mass and velocity.
are final mass and velocity. Here
and
.
The velocity of the truck be after its cargo is taken off is
Answer:
i) E = 269 [MJ] ii)v = 116 [m/s]
Explanation:
This is a problem that encompasses the work and principle of energy conservation.
In this way, we establish the equation for the principle of conservation and energy.
i)
At that point the speed 1 is equal to zero, since the maximum height achieved was 2.5 [km]. So this calculated work corresponds to the energy of the rocket.
Er = 269*10^6[J]
ii ) With the energy calculated at the previous point, we can calculate the speed developed.