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White raven [17]
2 years ago
12

One small thing you eat it you atomicly started crry. what is it.​

Physics
1 answer:
storchak [24]2 years ago
8 0

Answer:

it's green chilly or red chilly

Explanation:

I hope it's correct!

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Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 2.20×106 N , one at an angle 15.0 ∘ west of north,
Darina [25.2K]

Answer:

The total work done by the two tugboats on the supertanker is 3.44 *10^9 J

Explanation:

The force by the tugboats acting on the supertanker is constant and the displacement of the supertanker is along a straight line.

The angle between the 2 forces and displacement is ∅ = 15°.

First we have to calculate the work done by the individual force and then we can calculate the total work.

The work done on a particle by a constant force F during a straight line displacement s is given by following formula:

W = F*s

W = F*s*cos∅

With ∅ = the angles between F and s

The magnitude of the force acting on the supertanker is F of tugboat1 = F of tugboat 2 = F = 2.2 * 10^6 N

The total work done can be calculated as followed:

Wtotal = Ftugboat1 s * cos ∅1 + Ftugboat2 s* cos ∅2

Wtotal = 2Fs*cos∅

Wtotal = 2*2.2*10^6 N * 0.81 *10³ m s *cos15°

Wtotal = 3.44*10^9 Nm = <u>3.44 *10^9 J</u>

<u />

The total work done by the two tugboats on the supertanker is 3.44 *10^9 J

5 0
3 years ago
Which of the following most<br> directly limits the number of<br> organisms in a community?
astraxan [27]

Answer:

It can either be food, mating, or competition with other organisms for resources.

7 0
2 years ago
A steel bridge is 1000 m long at -20°C in winter. What is the change in length when the temperature rises to 40°C in summer? The
xenn [34]

Answer:

ΔL = 0.66 m

Explanation:

The change in length on an object due to rise in temperature is given by the following equation of linear thermal expansion:

ΔL = αLΔT

where,

ΔL = Change in Length of the bridge = ?

α = Coefficient of linear thermal expansion = 11 x 10⁻⁶ °C⁻¹

L = Original Length of the Bridge = 1000 m

ΔT = Change in Temperature =  Final Temperature - Initial Temperature

ΔT = 40°C - (-20°C) = 60°C

Therefore,

ΔL = (11 x 10⁻⁶ °C⁻¹)(1000 m)(60°C)

<u>ΔL = 0.66 m</u>

6 0
3 years ago
Leslie incorrectly balances an equation as 2C4H10 + 12O2 → 8CO2 + 10H2O.
tatiyna

Answer:

13 behind o2

Explanation:

answer is in photo above

4 0
3 years ago
What is true of all particles of gas enclosed within a container?
Andre45 [30]
Theyre all in constant motion

6 0
3 years ago
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