In addition to acceleration of gravity we experience centrifugal acceleration away from the axis of rotation of the earth. this additional acceleration has value ac = r w^2 where w = angular velocity and r is distance from your spot on earth to the earth's axis of rotation so r = R cos(l) where l = 60 deg is the lattitude and R the earth's radius and w = 1 / (24hr x 3600sec/hr)
<span>now you look up R and calculate ac then you combine the centrifugal acc. vector ac with the gravitational acceleration vector ag = G Me/R^2 to get effective ag' = ag -</span>
Answer:
center of mass of the two masses will lie at x = 2.52 cm
center of gravity of the two masses will lie at x = 2.52 cm
So center of mass is same as center of gravity because value of gravity is constant here
Explanation:
Position of centre of mass is given as
here we have
now we have
so center of mass of the two masses will lie at x = 2.52 cm
now for center of gravity we can use
here we have
now we have
So center of mass is same as center of gravity because value of gravity is constant here
yes she is very safe inside
Answer:
B = ρ g V_liquid
the thrust is proportional to the density of the liquid
Explanation:
The density of a liquid is defined as the relationship between the mass and the volume of the liquid
ρ = m / V
The upward push of the liquid is given by the principle of Archimedes Archimedes establishes that the push is equal to the weight of the dislodged liquid
B = W_liquid
B = m _liquid g
we substitute mass for density
B = ρ g V_liquid
therefore we see that the thrust is proportional to the density of the liquid
I this is tricky one sec.. I would go with b
