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Citrus2011 [14]
3 years ago
9

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a s

mall patch of light on the far wall. Having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. It appears that the central maximum is about 2 cmcm across, and you estimate that the distance from the window shade to the wall is about 5 mm.
Required:
Estimate the diameter of the pinhole.
Physics
1 answer:
DedPeter [7]3 years ago
5 0

Complete Question

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a small patch of light on the far wall. Having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. It appears that the central maximum is about 2 cm across, and you estimate that the distance from the window shade to the wall is about 5 m.

Required:

Estimate the diameter of the pinhole.  

Answer:

The diameter is  d =0.000336 m

Explanation:

     From the question we are told that

            The central maxima is D= 2cm = \frac{2}{100} = 0.02m

            The distance from the window shade is L = 5m

     The  average wavelength of the  sun is mathematically evaluated as

                         \lambda_{ave } = \frac{\lambda_i  + \lambda_f}{2}

 Generally the visible light spectrum  has a wavelength  range  between  400 nm  to 700 nm  

        So  the initial wavelength of the sun is \lambda _i = 400nm

           and the final wavelength is  \lambda_f = 700nm

  Substituting this into the above equation

                 \lambda_{sun} = \frac{400nm  +700nm}{2}

                        = 550nm

The diameter is evaluated as

              d = \frac{2.44 \lambda_{sun} L}{D}

substituting values

              d = \frac{2.44 * 550*10^{-9} * 5 }{0.02}

                d =0.000336 m

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These days magnets are made artificially in various shapes and sizes depending on their use. One of the most common magnets - the bar magnet - is a long, rectangular bar of uniform cross-section that attracts pieces of ferrous objects. The magnetic compass needle is also commonly used. The compass needle is a tiny magnet which is free to move horizontally on a pivot. One end of the compass needle points in the North direction and the other end points in the South direction.

The end of a freely pivoted magnet will always point in the North-South direction. The end that points in the North is called the North Pole of the magnet and the end that points South is called the South Pole of the magnet. It has been proven by experiments that like magnetic poles repel each other whereas unlike poles attract each other.

3 0
4 years ago
A 2cm length of wire centered on the origin carries a 20A current directed in the positive y direction. Determine the magnetic f
skad [1K]

Answer:

The magnetic field at a distance x = 5 m is 1.59 nT

Explanation:

Length of the wire, L = 2 cm = 0.02 m

Current, I = 20 A

x = 5 m

Magnetic field at a distance x = 5 m due to an infinitely long wire is given by:

B = \frac{\mu_{o}IL}{4\pi x\sqrt{x^{2} + L^{2}}}

B = \frac{4\pi\times 10^{- 7}\times 20\times 0.02}{4\pi \times 5\sqrt{5^{2} + 0.02^{2}}} = 1.59\times 10^{- 9}\ T

3 0
3 years ago
What is the average power supplied by a 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s?
Alchen [17]

A 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s has an average power of 560 W (Option b).

<h3>What is power?</h3>

Power is the work done over a period of time.

A secretary with a mass (m) of 60.0 kg runs up a 4.0 m (d) tall flight of stairs. Given gravity (g) is 9.81 m/s², the work (W) done is:

W = m × g × d = 60.0 kg × 9.81 m/s² × 4.0 m = 2.35 × 10³ J

They do 2.4 × 10³ J of work in 4.2 s (t). The average power (P) is:

P = W / t = 2.35 × 10³ J / 4.2 s = 560 W

A 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s has an average power of 560 W (Option b).

Learn more about power here: brainly.com/question/911620

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8 0
2 years ago
A 5.00-g bullet leaves the muzzle of a rifle with a speed of 320 m/s. the expanding gases behind it exert what force on the bull
muminat

Answer;

= 312 Newtons

Explanation;

The bullet has a mass of 0.005 kg, and a velocity of 320 m/s, so we need to find it's final kinetic energy.  

KE = 1/2*m*v^2

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      = 256 Joules.  

Divide this by the distance over which this energy was received and you have the force that provided that energy.  

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Rounded off, this is 312 N

3 0
3 years ago
A wagon weighs 1,800 N and is pulled by a horse at a speed of 0.40 meters/ second. What is the power of this horse
Alona [7]

Answer:

Power=720[watt]

Explanation:

We need to remember the definition of mechanical work which is equal to the product of the force applied by the distance traveled.

In this problem, we have to find the power which is defined as the work divided into the time in which such work is performed. This way if we have the displacement and the time, this will be the speed with which this work is done.

Power= W/T\\T=time [s]\\W=work [J]\\Power = F*V\\where\\V=velocity [m/s]\\Power=1800 * 0.4 = 720 [watt]

4 0
3 years ago
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