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astra-53 [7]
2 years ago
9

A car of mass 1500 kg is negotiating a flat circular curve of radius 50 m with a speed of 20 m/s.

Physics
1 answer:
Lilit [14]2 years ago
6 0

Answer:

Explanation:

a. The source of centripetal force on the car is  (3) the static friction force.

b. ac = v²/R = (20²)/50 = 8 m/s²

c.  Fc = m(ac) = 1500(8) = 12 kN

d. μ = Fc/N = Fc/mg = 12000 / 1500(9.8) = 0.8163... ≈ 0.82

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The Nucleus

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What is the mass of a large ship that has a momentum of 1.60x10^9 kg*m/s and is moving at a velocity of 10m/s?
Elden [556K]

Answer:

160000000 kg.

Explanation:

p=mv

p=1.6x10^9

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rearrange and substitute:

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An archer fires an arrow at a castle 230 m away. The arrow is in flight for 6 seconds, then hits the wall of the castle and stic
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Answer:

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(b). The angle is 39.90°.

Explanation:

Given that,

Horizontal distance = 230 m

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R =u\cos\theta t

Put the value into the formula

\dfrac{230}{6} = u\cos\theta

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We need to calculate the height

Using vertical component

H=u\sin\theta t-\dfrac{1}{2}gt^2

Put the value in the equation

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u\sin\theta=\dfrac{16+9.8\times18}{6}

u\sin\theta=32.06.....(II)

Dividing equation (II) and (I)

\dfrac{u\sin\theta}{u\cos\theta}=\dfrac{32.06}{38.33}

\tan\theta=0.8364

\theta=\tan^{-1}0.8364

\theta=39.90^{\circ}

(a). We need to calculate the initial speed

Using equation (I)

u\cos\theta\times t=38.33

Put the value into the formula

u =\dfrac{230}{6\times\cos39.90}

u=49.96\ m/s

(b). We have already calculate the angle.

Hence, (a). The initial speed of the arrow is 49.96 m/s.

(b). The angle is 39.90°.

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3 years ago
a dump truck travels 70mph for 3 hours, then for 20mph for another 2 hours in the same direction. what is the average speed the
Dmitry_Shevchenko [17]

Answer:

the average speed of the car is 170 mph.

Explanation:

Given;

initial speed, u = 70 mph

time of motion, t₁ = 3 hours

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time of motion, t₂ = 2 hours

The average speed of the car is calculated as;

v' = \frac{70(3) - 20(2)}{3-2} \\\\v' = 170 \ mph

Therefore, the average speed of the car is 170 mph.

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