Answer:
Some examples of the uses of a screw are in a jar lid, a drill, a bolt, a light bulb, faucets, bottle caps and ball point pens.
Explanation:
Explanation:
As the given spheres are connected by a thin wire so, the potential on the spheres are the same.
......... (1)
Hence, total charge will be as follows.
= Q = -95.5 nC .......... (2)
Using the above two equations, the final equation will be as follows.

and, 
Hence, we will calculate the charge on sphere B after the equilibrium is reached as follows.

= 
= 82.714 nC
Thus, we can conclude that the charge on sphere B after equilibrium has been reached is 82.714 nC.
Answer:1 trip around the earth is an angular displacement of 2*pi
3.6525*10^2 days
I
Explanation:24 h/1 day * 3.600*10^3 s/1h = 3.156*10^7 s
Angular speed = angular displacement / time
Angular speed = 2*pi rads / 3.156*10^7 s = 1.9910*10^-7 rad/s
Answer:
Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.
Explanation:
hope this helps!
Explanation:
It is given that,
Focal length of the concave mirror, f = -13.5 cm
Image distance, v = -37.5 cm (in front of mirror)
Let u is the object distance. It can be calculated using the mirror's formula as :



u = -21.09 cm
The magnification of the mirror is given by :


m = -1.77
So, the magnification produced by the mirror is (-1.77). Hence, this is the required solution.