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Aleks [24]
3 years ago
5

A grocery shopper tosses a(n) 8.5 kg bag of rice into a stationary 17.7 kg grocery cart. The bag hits the cart with a horizontal

speed of 6.9 m/s toward the front of the cart. What is the final speed of the cart and bag? Answer in units of m/s.
Physics
1 answer:
timama [110]3 years ago
4 0

Answer:

2.2386 m/s

Explanation:

I think you would use the momentum equation.

m1v1=m2v2

m1= mass of the bag (8.5kg)

v1= speed of bag (6.9 m/s)

m2= mass of bag and cart (26.2 kg)

v2= speed of cart and bag

Plug these numbers all into the equation and you solve for v2 which ends up at 2.2386 m/s

You might be interested in
Newton’s second law of motion addresses the relationship between what two variables that influence the force on a body?
IgorC [24]

Newton’s Second Law concerns the generation of force based on an object’s mass and acceleration, as described by the equation F=ma.

Hope this helps!

8 0
3 years ago
Read 2 more answers
What is the anion of the ionic compound NaC2H3O2<br><br> thank you!
KIM [24]

C₂H₃O₂⁻ is an anion.

<u>Explanation:</u>

NaC₂H₃O₂(s)   →  Na⁺(aq)  +  C₂H₃O₂⁻(aq)

NaC₂H₃O₂ when dissociated, yields Na⁺ and C₂H₃O₂⁻.

Anion is a negatively charged ion.

In this case,  C₂H₃O₂⁻ is an anion.

6 0
3 years ago
Write down the (real) electric and magnetic fields for a monochromatic plane wave of amplitude E0 , frequency w, and phase angle
jeka57 [31]

Answer:

a) the oscillation of this field is in phase, when the magnetic field goes in the negative direction of y, the elective field goes in the positive direction of the z axis

b) the direction of the magnetic field perpendicular to this electric field and the speed in the negative x the magnetic field goes in the x direction and in the direction (1, - 1.1)

Explanation:

a) the polarization the determined wave oscillates the electric field, which is the z axis

 As the wave travels on the negative x-axis and the magnetic field is perpendicular, this field goes on the positive y-axis

the oscillation of this field is in phase, when the magnetic field goes in the negative direction of y, the elective field goes in the positive direction of the z axis

be) in the case of a polarization in the xi plane the magnetic field must go in the direction of the magnetic field perpendicular to this electric field and the speed in the negative x the magnetic field goes in the x direction and in the direction (1, - 1.1)

3 0
3 years ago
A mass M is attached to an ideal massless spring. When this system is set in motion with amplitude A, it has a period T. What is
cricket20 [7]

Answer:

<em>The period of the motion will still be equal to T.</em>

<em></em>

Explanation:

for a system with mass = M

attached to a massless spring.

If the system is set in motion with an amplitude (distance from equilibrium position) A

and has period T

The equation for the period T is given as

T = 2\pi \sqrt{\frac{M}{k} }

where k is the spring constant

If the amplitude is doubled, the distance from equilibrium position to the displacement is doubled.

Increasing the amplitude also increases the restoring force. An increase in the restoring force means the mass is now accelerated to cover more distance in the same period, so the restoring force cancels the effect of the increase in amplitude. Hence, <em>increasing the amplitude has no effect on the period of the mass and spring system.</em>

5 0
3 years ago
When a parachutist jumps from an airplane, he eventually reaches a constant speed, called the terminal speed. Once he has reache
Masteriza [31]

Answer:

b) True.    the force of air drag on him is equal to his weight.

Explanation:

Let us propose the solution of the problem in order to analyze the given statements.

The problem must be solved with Newton's second law.

When he jumps off the plane

     fr - w = ma

Where the friction force has some form of type.

     fr = G v + H v²

Let's replace

     (G v + H v²) - mg = m dv / dt

We can see that the friction force increases as the speed increases

At the equilibrium point

      fr - w = 0

      fr = mg

      (G v + H v2) = mg

For low speeds the quadratic depended is not important, so we can reduce the equation to

     G v = mg

     v = mg / G

This is the terminal speed.

Now let's analyze the claims

a) False is g between the friction force constant

b) True.

c) False. It is equal to the weight

d) False. In the terminal speed the acceleration is zero

e) False. The friction force is equal to the weight

3 0
3 years ago
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